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Grace [21]
3 years ago
9

A scuba diver stays underwater for 30 minutes. How is this possible when the air tank is so small?​

Physics
1 answer:
irina1246 [14]3 years ago
6 0

Answer:

Here's the answer:

Explanation:

An average open-water certified diver using a standard aluminium 80-cubic-foot tank on a 40-foot dive will be able to stay down for about 45 to 60 minutes before surfacing with a safe reserve of air still in the tank.

Three Factors That Determine How Long a Diver's Air Will Last:

1. Tank Volume

2. Depth

3. Air Consumption Rate

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Two groups of scientists got different results while studying about the evolution of the universe. Which of these statements bes
aliya0001 [1]
The one that would explain why the two groups of scientists got different results is : 
They had different specialties and interpreted their data differently
Probably one analyze it with x theory and the other use y theory

hope this helps
3 0
3 years ago
Read 2 more answers
A fast-food restaurant uses a conveyor belt to send the burgers through a grilling machine. if the grilling machine is 1.2 m lon
Vinil7 [7]

length of the grilling machine is 1.2 m

time taken to cook the burger is 2.7 min = 162 s

so the speed of the machine should be like this that if must have to cook till it cross the machine

v = \frac{d}{t}

v = \frac{1.2}{162}

v = 7.41* 10^{-3} m/s

now in one minute the total length of the machine that is covered is given by

L = v*t

L = 7.41*10^{-3}* 60 = 44.4 cm

now distance between the burgers is 15 cm

so total production rate will be

N = \frac{44.4}{15} = 3 burger/min

so it will produce 3 burger per minute

8 0
3 years ago
If a force of 19 N is applied to a crate to push it 23 m, how much work is done on the crate by the force?
swat32

Answer:

437 Joules

Explanation:

Use the formula for work directly

(work) = (force) x (displacement)

to get

(work) = (19 N) x (23 m) = 437 Joules

4 0
3 years ago
A net force of 20 N acting on a wooden block produces an
Ymorist [56]

Answer:

From the second law of motion:

F = ma

we are given that the force applied on the block is 20N and the block accelerates at an acceleration of 4 m/s/s

So, F=  20N   and  a = 4 m/s/s

Replacing the variables in the equation:

20 = 4* m

m = 20 / 4

m = 5 kg

5 0
3 years ago
A steel beam of mass 1975 kg and length 3 m is attached to the wall with a pin that can rotate freely on its right side. A cable
Nuetrik [128]

Answer:

a) 29062.125 N·m

b) 0 N·m

c) Torque, due \ to \ tension =L\cdot Tsin\theta = \frac{M\cdot L\cdot g}{2}

d) T = 11186.02 N

Explanation:

We are given

Beam mass = 1975 kg

Beam length = 3 m

Cable angle = 60° above horizontal

a) We have the formula for torque given as follows;

Torque about the pin = Force × Perpendicular distance of force from pin

Where the force = Force due to gravity or weight, we have

Weight = Mass × Acceleration due to gravity = 1975 × 9.81 = 19374.75 N

Point of action of force = Midpoint for a uniform beam = length/2

∴ Point of action of force = 3/2 = 1.5 m

Torque due to gravity = 19374.75 N × 1.5 m = 29062.125 N·m

b) Torque about the pinned end due to the contact forces between the pin and the beam is given by the following relation;

Since the distance from pin to the contact forces between the pin and the beam is 0, the torque which is force multiplied by perpendicular distance is also 0 N·m

c) To find the expression for the tension force, T we find the sum of the moment forces about the pin as follows

Sum of moments about p is given as follows

∑M = 0 gives;

T·sin(θ) × L= M×L/2×g

Therefore torque due to tension is given by the following expression

Torque, due \ to \ tension =L\cdot Tsin\theta = \frac{M\cdot L\cdot g}{2}

d) Plugging in the values in the torque due to tension equation, we have;

3\times Tsin60 = \frac{1975\times 3\times 9.81}{2} = 29062.125

Therefore, we make the tension force, T the subject of the formula hence

T= \frac{29062.125}{3 \times sin(60)} = 11186.02 N

8 0
3 years ago
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