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Afina-wow [57]
3 years ago
5

What is the fraction of the hydrogen atom's mass (11h) that is in the nucleus? the mass of proton is 1.007276 u, and the mass of

11h atom is 1.007825 u. express your answer using four significant figures?
Chemistry
1 answer:
ololo11 [35]3 years ago
3 0
Hello there!

To determine the fraction of the hydrogen atom's mass that is in the nucleus, we have to keep in mind that a Hydrogen atom has 1 proton and 1 electron. Protons are in the nucleus while electrons are in electron shells surrounding the nucleus. The mass of the nucleus will be equal to the mass of 1 proton and we can express the fraction as follows:

Mass Fraction= \frac{mass 1 Proton}{mass H atom} = \frac{1,007276 u}{1,007825}=0,9995

So, the fraction of the hydrogen atom's mass that is in the nucleus is 0,9995. That means that almost all the mass of this atom is at the nucleus.

Have a nice day!
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Hydrogen and chlorine react to form hydrogen chloride, like this:
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Answer:

the value of the equilibrium constant Kp for this reaction is 0.275

Explanation:

Step 1: Data given

Pressure HCl at the equilibrium = 18.0 atm

Pressure H2 at the equilibrium = 25.4 atm

Pressure Cl2 at the equilibrium = 46.4 atm

Step 2: The balanced equation

H2(g) + Cl2(g) → 2 HCl(g)

Step 3: Calculate the value of the equilibrium constant Kp for this reaction

Kp = (pHCl)² / (pH2*pCl2)

Kp = 18.0² / (25.4 * 46.4)

Kp = 324 / 1178.56

Kp = 0.275

the value of the equilibrium constant Kp for this reaction is 0.275

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Group the following electron configurations in pairs that would represent similar chemical properties at their atoms;
marishachu [46]

<u>Answer:</u> Pairs are:  (a) and (d), (b) and (f), (c) and (e)

<u>Explanation:</u>

In a periodic table, elements are arranged in 18 vertical columns known as groups and 7 horizontal rows known as periods.

Elements arranged in a group show similar chemical properties because of the presence of same number of valence electrons.

Valence electrons are defined as the electrons which are present in the outermost shell of an atom. Outermost shell has the highest value of 'n' that is principal quantum number.

For the given options:

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The given electronic configuration is:  1s^22s^22p^63s^2

The number of valence electrons in the given configuration are 2

  • <u>For b:</u>

The given electronic configuration is:  1s^22s^22p^63s^3

The number of valence electrons in the given configuration are [2 + 3] = 5

  • <u>For c:</u>

The given electronic configuration is:  1s^22s^22p^63s^23p^64s^23d^{10}4p^6

The number of valence electrons in the given configuration are [2 + 6] = 8

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The given electronic configuration is:  1s^22s^2

The number of valence electrons in the given configuration are 2

  • <u>For e:</u>

The given electronic configuration is:  1s^22s^22p^6

The number of valence electrons in the given configuration are [2 + 6] = 8

  • <u>For f:</u>

The given electronic configuration is:  1s^22s^22p^63s^23p^3

The number of valence electrons in the given configuration are [2 + 3] = 5

Electronic configuration of (a) and (d) will form a pair, (b) and (f) will form a pair, (c) and (e) will form a pair and will have similar chemical properties.

Hence, the pairs are:  (a) and (d), (b) and (f), (c) and (e)

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