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Afina-wow [57]
3 years ago
5

What is the fraction of the hydrogen atom's mass (11h) that is in the nucleus? the mass of proton is 1.007276 u, and the mass of

11h atom is 1.007825 u. express your answer using four significant figures?
Chemistry
1 answer:
ololo11 [35]3 years ago
3 0
Hello there!

To determine the fraction of the hydrogen atom's mass that is in the nucleus, we have to keep in mind that a Hydrogen atom has 1 proton and 1 electron. Protons are in the nucleus while electrons are in electron shells surrounding the nucleus. The mass of the nucleus will be equal to the mass of 1 proton and we can express the fraction as follows:

Mass Fraction= \frac{mass 1 Proton}{mass H atom} = \frac{1,007276 u}{1,007825}=0,9995

So, the fraction of the hydrogen atom's mass that is in the nucleus is 0,9995. That means that almost all the mass of this atom is at the nucleus.

Have a nice day!
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How does one Coulomb of charge compare with the charge of a single electron?
fgiga [73]
The charge of an e- is 1.60217657×10^-19 coulombs I.e. A very small number!
So 1 coulomb is much much bigger than the charge of an electron.
5 0
4 years ago
Chemistry question, 20 points, will mark as brainliest if correct:
Brums [2.3K]

Answer:

CS2 + 3O2 -> CO2 + 2SO2

Explanation:

3 0
2 years ago
Chloroform, formerly used as an anaesthetic and now believed to be a carcinogen, has a heat of vaporization ΔHvaporization = 31.
djverab [1.8K]

Answer:

Chloroform is expected to boil at 333 K (60 ^{0}\textrm{C}).

Explanation:

For liquid-vapor equilibrium at 1 atm, \Delta G^{0} = 0.

We know, \Delta G^{0}=\Delta H^{0}-T\Delta S^{0} , where T is temperature in kelvin scale.

Here both \Delta H^{0} and \Delta S^{0} are corresponding to vaporization process therefore T represents boiling point of chloroform.

So, 0=(31.4\times 10^{3}\frac{J}{mol})-[T\times (94.2\frac{J}{mol.K})]

or, T = 333 K

So, at 333 K (60 ^{0}\textrm{C}) , chloroform is expected to boil.

6 0
3 years ago
Read 2 more answers
400 ml of a 75 M solution of H2SO4 is needed to for a lab. The stock solution is 16.0 M. Calculate how much stock is needed to m
Len [333]

Answer:

The volume of stock solution needed to make the solution is 1875 ml

Explanation:

The parameters given are;

The volume of 75 M solution of H₂SO₄ = 400 ml

The concentration of stock solution = 16.0 M

Number moles per liter of stock solution = 16 moles

Number of moles in required 400 ml solution = 0.4×75 = 30 M

Volume of stock solution that contains 30 M = 30/16×1 = 1.875 l

The volume of stock solution that is required = 1875 ml

4 0
3 years ago
How fast should you heat the melting point sample?
hichkok12 [17]

Answer:

Option a.

Explanation:              

The transformation of a solid into liquid is a slow process, hence a rate of heating too fast, near the melting point of the sample, will not give the right time to the crystals of the sample to absorb the heat and to melt in the outside and the inside, leading to wrong results in all cases. If we heat to fast, the melting point range will be too broad and will be misleading, resulting in values of the range more hight than the theoric ones.  

A rate of 1 °C/min or 2 °C/min is the most appropriate to approach the melting point of the sample. Since it is too slow, from preventing the experiment taking forever it is recommended to start the experiment at a high heating rate until it reaches 20 °C below the melting point, and then, turn the heating rate down to 1 °C/min or 2 °C/min.      

Therefore, the correct answer is a: near the melting point of the sample, we must heat slowly until it reach the expected temperature.

I hope it helps you!

7 0
3 years ago
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