<span>Evaporation
is a type of vaporization of a liquid that occurs from the surface of a
liquid into a gaseous phase that is not saturated with the evaporating
substance. The other type of vaporization is boiling, which is
characterized by bubbles of saturated vapor forming in the liquid phase.</span>
Answer: C5H14N2
Explanation:
The element mass are:
C = 58.77 g
H = 13.81 g
N = 27.42 g
To get their moles, we have to divide by the molar mass which will be:
C: 58.77 / 12.01 = 4.8934
H: 13.81 / 1.008 = 13.7004
N: 27.42 / 14.01 = 1.9572
We then divide by the smallest mole which will be:
C: 4.8934 / 1.9572 = 2.5
H: 13.7004 / 1.9572 = 7
N: 1.9572 / 1.9572 = 1
We then multiply by 2 so that we can get whole number ratio:
C: 2.5 × 2 = 5
H: 7 × 2 = 14
N: 1 × 2 = 2
Therefore, the empirical formula will be = C5H14N2
Explanation:
The correct answer is C.
Through runoff on Earth's surface. Hope this helped!
Answer:
6 H⁺ + BrO₃⁻ + 3 Sb³⁺ ⟶ Br⁻ + 3 H₂O + 3 Sb⁵⁺
Explanation:
Step 1: Write the unbalanced reaction
BrO₃⁻ + Sb³⁺ ⟶ Br⁻ + Sb⁵⁺
Step 2: Identify both half-reactions
Reduction: BrO₃⁻ ⟶ Br⁻
Oxidation: Sb³⁺ ⟶ Sb⁵⁺
Step 3: Perform the mass balance, adding H⁺ and H₂O where appropriate
6 H⁺ + BrO₃⁻ ⟶ Br⁻ + 3 H₂O
Sb³⁺ ⟶ Sb⁵⁺
Step 4: Perform the charge balance, adding electrons where appropriate
6 H⁺ + BrO₃⁻ + 6 e⁻ ⟶ Br⁻ + 3 H₂O
Sb³⁺ ⟶ Sb⁵⁺ + 2 e⁻
Step 5: Multiply both half-reactions by numbers that assure that the number of electrons gained and lost is the same
1 × (6 H⁺ + BrO₃⁻ + 6 e⁻ ⟶ Br⁻ + 3 H₂O)
3 × (Sb³⁺ ⟶ Sb⁵⁺ + 2 e⁻)
Step 6: Add both half-reactions and cancel what is repeated in both sides
6 H⁺ + BrO₃⁻ + 3 Sb³⁺ ⟶ Br⁻ + 3 H₂O + 3 Sb⁵⁺
Answer:
Valency of the two elements
Explanation:
In order to correctly formularize the compound, the student needs to ask of the valences of the elements involved.
Chlorine has valency of -1, while Barium +2.
The exchange of valency gives the formula .
Another explanation is that Barium donates 2 electrons which the chlorine atoms accept, in order to form the covalent bond.
I hope this was helpful.