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spin [16.1K]
3 years ago
12

Assume that charge −q is placed on the top plate, and +q is placed on the bottom plate. What is the magnitude of the electric fi

eld E between the plates? Express E in terms of q and other quantities given in the introduction, in addition to ϵ0 and any other constants needed..
Physics
1 answer:
Anna [14]3 years ago
8 0

Answer:

 E=\frac{q}{\epsilon_oA}  

Explanation:

Let the area of each plate be A.

From Gauss Law,

\phi=\frac{q}{\epsilon_o}

\phi=E.A

\Rightarrow E.A=\frac{q}{\epsilon_o}\\\Rightarrow E=\frac{q}{\epsilon_oA}

Thus, using Gauss law, electric field between the plates is:

E=\frac{q}{\epsilon_oA}

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You are at a train station, standing next to the train at the front of the first car. The train starts moving with constant acce
Aleksandr [31]

The time needed for the 7th car to pass is 13.2 s

Explanation:

The motion of the train is a uniformly accelerated motion, therefore we can use suvat equations.

We start by analzying the motion of the first car, by using the equation:

s=ut+\frac{1}{2}at^2

where

s is the distance covered by the first car in a time t, which corresponds to the length of one car

u = 0 is the initial velocity

a is the acceleration

t = 5.0 s is the time

The equation can be rewritten as

a=\frac{2s}{t^2}=\frac{2L}{(5.0)^2}=0.08L[m/s^2]

where L is the length of one car.

The same equation can be written considering the first 7 cars:

7L = ut+\frac{1}{2}at'^2

where

7L is the distance covered by the 7 cars

t' is the time needed

We still have

u = 0

And the acceleration is constant so it is

a=0.08L

Substituting into the equation, we can find t':

7L = \frac{1}{2}(0.08L)t'^2\\7=0.04t'^2\\t'=\sqrt{\frac{7}{0.04}}=13.2 s

In attachment the graph of the distance covered versus the time taken: since the motion is uniformly accelerated, the relationship between the two variables is quadratical.

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

8 0
3 years ago
Suppose Earth orbited a star whose mass was double the mass of the sun. If the radius of Earth’s orbit remained the same as it i
Vaselesa [24]

Answer:

Two times as much

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The equation for gravitational force is: Fg = GMm/r^2 with G being the universal gravitational constant.

So to make things easier we'll set r equal to 1 since it's a constant as well as G.

Then we're left with Fg=Mm with M being the mass of the sun and m being the mass of the earth.

So if m is constant and supposedly equals 1 then Fg=M so Fg is proportional to M therefore if M doubles then Fg doubles.

7 0
2 years ago
Determine the radial acceleration of the ultracentrifuge using calculations
Dmitry [639]

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\text { Centripetal acceleration }=\frac{\text {velocity}^{2}}{\text {radius of motion}}

\mathrm{a}_{\mathrm{rad}}=\frac{V^{2}}{r}

where,

\text { and }=\text { radial, or centripetal, acceleration }(\mathrm{m} / \mathrm{s} ^2)

"v" = "velocity" (m/s) and "r" = "radius of motion of the object" (m)

3 0
3 years ago
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