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spin [16.1K]
3 years ago
12

Assume that charge −q is placed on the top plate, and +q is placed on the bottom plate. What is the magnitude of the electric fi

eld E between the plates? Express E in terms of q and other quantities given in the introduction, in addition to ϵ0 and any other constants needed..
Physics
1 answer:
Anna [14]3 years ago
8 0

Answer:

 E=\frac{q}{\epsilon_oA}  

Explanation:

Let the area of each plate be A.

From Gauss Law,

\phi=\frac{q}{\epsilon_o}

\phi=E.A

\Rightarrow E.A=\frac{q}{\epsilon_o}\\\Rightarrow E=\frac{q}{\epsilon_oA}

Thus, using Gauss law, electric field between the plates is:

E=\frac{q}{\epsilon_oA}

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