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Elodia [21]
3 years ago
10

What is special about decomposers? *

Physics
1 answer:
Bogdan [553]3 years ago
5 0
D. They are heterotrophs that digest food internally.
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Is bleach heterogeneous
irga5000 [103]
No, bleach is not heterogeneous. Bleach is actually homogeneous. 
Heterogeneous is if it the same throughout. 
Homogeneous is if it is different (has chunks and clumps of different materials)
6 0
3 years ago
Two students are watching a person riding a skateboard up and down a ramp. Each student shares what they think about the energy
Setler79 [48]

Answer:

The correct option is;

Raymond: I think the skateboarder has the same total energy at all points on the ramp

Explanation:

The total energy, also known as the total mechanical energy, is the sum of the kinetic and potential energies of the skateboarder

Given that the potential energy is the energy gained due to elevation, the maximum potential energy is obtained at the top of the ramp, while the maximum kinetic energy, which is the energy due to motion, is at the bottom of the ramp where the skateboarder moves fastest.

However, by the energy conservation principle, the kinetic energy of he skateboarder comes from the conversion of the potential energy, such that the total energy is the same at any particular point on the ramp.

6 0
2 years ago
PLEASE HELP URGENT!!!!!!!!!!!!!
Nimfa-mama [501]

c i think sorry if wrong

4 0
3 years ago
What is the direction of the sum of these two vectors? ​
gayaneshka [121]

Answer:

what is the direction of the sum of these two vectors?

7 0
2 years ago
Read 2 more answers
A thin, rectangular sheet of metal has mass M and sides of length a and b. Find the moment of inertia of this sheet about an axi
Lubov Fominskaja [6]

Answer:

The moment of inertia is I=\frac{M}{12} a^{2}

Explanation:

The moment of inertia is equal:

I=\int\limits^a_b {r^{2} } \, dm

If r is -\frac{a}{2}

and dm=\frac{M}{a} dr

I=\int\limits^a_b {r^{2}\frac{M}{a}  } \, dr\\a=\frac{a}{2} \\b=-\frac{a}{2}

I=\frac{M}{a} \int\limits^a_b {r^{2}  } \, dr\\\\I=\frac{M}{a} (\frac{M}{3} )_{b}^{a}\\  I=\frac{M}{3a} (\frac{a^{3} }{8} +\frac{a^{3} }{8} )\\I=\frac{M}{12} a^{2}

7 0
3 years ago
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