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Marianna [84]
3 years ago
7

The concentration of hydronium ions is greater than 1 × 10–7 for basic solutions. True False

Chemistry
1 answer:
Nataly [62]3 years ago
5 0

Answer : The given statement is, false.

Explanation :

Ionic product of water : It is defined as the product of the concentration of hydrogen ion and the concentration of hydroxide ion.

The mathematical expression will be,

[H^+][OH^-]=10^{-14}

When the concentration of hydrogen ion and hydroxide ion are equal then the solution is neutral and the value will be, 1\times 10^{-7}. And the pH of the solution is, 7.

When the concentration of hydrogen ion is greater than 1\times 10^{-7} then the solution is acidic in nature. And the pH of the solution is, less than 7.

When the concentration of hydrogen ion is less than 1\times 10^{-7} then the solution is basic in nature. And the pH of the solution is, greater than 7.

Hence, the given statement is false.

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A 100.00 ml of volume of 0.500 M HCl was mixed with 100.00 ml of 0.500 M KOH in a constant pressure calorimeter. The initial tem
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Answer:

The heat of the reaction = -1985 J = -1.985 kJ

The enthalpy of the reaction is -39.7 kJ/ mol

Explanation:

<u>Step 1: </u>Data given

Volume of HCl = 100 mL the heat of the reaction = 0.1 L

Molarity of HCl solution = 0.500 M

Volume of KOH = 100 mL = 0.1 L

Molarity of KOH solution = 0.500 M

Initial temperature = 23.0 °C

Final temperature = 25.5 °C

Specific heat of the solution = 3.97 J/°C *g

Density of the solution = 1g/ mL

<u>Step 2: </u>Calculate heat

Q = m*c*ΔT

with m = the mass of both solution : 100g + 100 g ( since density = 1g/mL) = 200 g

c = the specific heat = 3.97 J/°C*g

ΔT  = T2 -T1 = 25.5 = 23 = 2.5 °C

Q = 200g *3.97 J/°C*g * 2.5°C = 1985 J  (= -1985 J because it's exothermic)

<u />

<u>Step 3:</u> Calculate the number of moles

Number of moles = Molarity * Volume

Number of moles = 0.5 * 0.1 L = 0.05 moles

(Moles of the acid are equal to the moles of water produced.

Moles of solution = 0.05 moles)

<u>Step 4: </u>Calculate the enthalpy of the reaction

ΔH = heat change /Number of moles

    = -1.985 kJ/ 0.05 moles

   =- 39700 J/mol = -39.7 kJ/ mol

The enthalpy of the reaction is -39.7 kJ/ mol

The enthalpy of the reaction is negative, this means the reaction is exothermic ( which means the final temperature is higher than the initial temperature.)

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