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Nikitich [7]
2 years ago
14

Two similar sized stones, one heavy and one light, are dropped from the same height into a pond. Explain why the impact of the h

eavy stone would produce waves with higher amplitude than the impact of the light done would.
Physics
2 answers:
Artemon [7]2 years ago
7 0
The mass of the object affects the force, as shown in the equation f=ma or force = mass times acceleration. The stone with the higher mass would emit a greater force on the water, causing it to be displaced and wave. the stones would actually fall at the same speed.
Sophie [7]2 years ago
5 0
The impact of the heavy stone would produce waves with a higher amplitude because the stone would pick up more speed while falling.


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The following diagram represents a cart with an initial velocity of 1.0 m/s sliding along a frictionless track from point A
ki77a [65]

Answer:

point b

Explanation:

7 0
3 years ago
Estimate the mass of the Great Pyramid of Giza, in tons. You make may use of the following information: the Great Pyramid is in
postnew [5]

Answer:

6005803.83105 short tons

Explanation:

The definition of density is \rho = \frac{m}{V}, and the volume of a pyramid is (confusingly written on the proposal) V=\frac{1}{3} Ah, so we can write:

m=\rho V=\rho V \frac{1}{3} Ah=\rho V \frac{1}{3} s^2h

Where s is the side of the base, being s^2 the area of that square.

We will write everything in S.I., and the best way to convert units is using conversion factors, for example, since 1m=100cm, we know that \frac{1m}{100cm}=1, and we can use this factor to convert anything written in cm to anything written in m. Example:

500cm=500cm\frac{1m}{100cm}=5m

Here we just multiplied 500cm by something that is equal to 1 (as every conversion factor must), so <em>it's not doing anything but changing the units</em>.

We can use this tool like this:

2.1\frac{g}{cm^3}=2.1\frac{g}{cm^3}(\frac{1Kg}{1000g})(\frac{100cm}{1m})^3=2100Kg/m^3

Where we have used the fact that 1^3=1 (<u>we can elevate any conversion factor to any number and they still will be 1</u>) and where we have placed strategically what is the numerator and what in the denominator so the units we don't want cancel out and the units we want appear.

Substituting then our values:

m=\rho V \frac{1}{3} s^2h=(2100Kg/m^3)\frac{1}{3} (230.34m)^2(146.7m)=5448373586.96Kg

And now we will convert to short tons using two conversion factors at the same time:

m=5448373586.96\ Kg(\frac{1\ lb}{0.45359237\ Kg})(\frac{1\ short\ ton}{2000\ lb} )=6005803.83105\ short \ tons

Remember, their value is 1, and we place the units to cancel the ones we don't want and keep the ones we want, here Kg cancel out, and lb cancel out, leaving the short tones.

8 0
2 years ago
A rock is lifted by a machine to a height of 10m. If it has a mass of 22 kilograms
zmey [24]

Answer:

2156J

Explanation:

Given parameters:

Height of lift  = 10m

Mass  = 22kg

Unknown:

Work done by the machine  = ?

Solution:

Work done is the force applied to move a body through a certain distance.

So;

        Work done  = Force x distance

Here;

       Work done  = mass x acceleration due to gravity x height

      Work done  = 22 x 9.8 x 10  = 2156J

5 0
3 years ago
11. A car travels at 25 m/s to the North. It has an acceleration of 2 m/s’ to the south
Anna11 [10]

Answer:

delta x= 100m

Explanation:

vi= 25 meters

a= -27meters

t=20s

find delta x

4 0
2 years ago
I need your opinion on this
DiKsa [7]
Block that fool, move on, take a nice warm bath, but on some music and vibe dawg, it might be hard to get over something like this, but just know that person was in the wrong the whole time.
5 0
2 years ago
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