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Alecsey [184]
3 years ago
6

A battery does work on electric charges to bring them to a position of higher electric potential energy so that they can flow th

rough a circuit to a lower potential energy. the potential difference between the terminals of a battery, when no current flows to an external circuit, is referred to as the terminal voltage. the internal resistance of a battery decreases with decreasing temperature. a battery is a device that produces electricity by transforming chemical energy into electrical energy.\
Physics
1 answer:
Ipatiy [6.2K]3 years ago
7 0
(Missing question is: which of the following statements are true?)

a) <span>A battery does work on electric charges to bring them to a position of higher electric potential energy so that they can flow through a circuit to a lower potential energy --> TRUE
That's true: the battery does the work to move the charges to one end of its terminal thus creating a potential difference between the two terminals. Then, when it is connected to the circuit, charges start to flow to the terminal at lower potential (through the circuit)

b) </span><span>the potential difference between the terminals of a battery, when no current flows to an external circuit, is referred to as the terminal voltage --> FALSE
This is false: when no current flows, it is called e.m.f. (electromotive force)

c) </span><span>the internal resistance of a battery decreases with decreasing temperature 
--> TRUE
In fact, the dependence of a resistance with the temperature is:
</span>R=R_0[1+\alpha (T-T_0)]
with \alpha being generally positive, therefore the value of the resistance is proportional to T, and when T decreases, R decreases as well.

<span>d) a battery is a device that produces electricity by transforming chemical energy into electrical energy --> TRUE
</span><span>That's true: a battery uses chemical reactions to create a potential difference between the two terminals that can be exploited to make charges flowing through a circuit.


</span>
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A mass free to vibrate on a level, frictionless surface at the end of a horizontal spring is pulled 35 cm from its equilibrium p
saul85 [17]

Answer:

0.67 s

Explanation:

This is a simple harmonic motion (SHM).

The displacement, x, of an SHM is given by

x = A\cos(\omega t)

A is the amplitude and \omega is the angular frequency.

We could use a sine function, in which case we will include a phase angle, to indicate that the oscillation began from a non-equilibrium point. We are using the cosine function for this particular case because the oscillation began from an extreme end, which is one-quarter of a single oscillation, when measured from the equilibrium point. One-quarter of an oscillation corresponds to a phase angle of 90° or \frac{\pi}{4} radian.

From trigonometry, \sin A =\cos B if A and B are complementary.

At t = 0, x = 3.5

3.5 = A\cos(\omega \times0)

A =3.5

So

x = 3.5\cos(\omega t)

At t = 0.12, x = 1.5

1.5 = 3.5\cos(0.12\omega)

\cos(0.12\omega)=\dfrac{1.5}{3.5}=0.4286

0.12\omega =\cos^{-1}0.4286

0.12\omega = 1.13

\omega = 9.4

The period, T, is related to \omega by

T = \dfrac{2\pi}{\omega} = \dfrac{2\times3.14}{9.4}=0.67

5 0
3 years ago
think of two school rules and briefly describe how these rules help protect health and why its important to follow them.
Softa [21]

Answer:

Wash your hand when you are done using the restroom because you could spread germs if not.

Don't come to school if you are sick because then you will get others sick.

Explanation:

5 0
3 years ago
Read 2 more answers
What type on msd causes inflammation of the tendons that correct bones to muscles
svp [43]

I believe it would be Tendonitis

8 0
3 years ago
please help me guys please please please please please please please please please please please please please​
seropon [69]

Answer:

1.F = 256 N

2.a = 8 m/s/s

By looking at the given information, you know force, and an acceleration. Therefore you have enough information to use the first formula.

F = ma

256 N = m * 8 m/s/s

m = 256 N/8 m/s/s

m = 32 Kg

6 0
3 years ago
Two sources of light of wavelength 720 nm are 10 m away from a pinhole of diameter 1.2 mm. How far apart must the sources be for
julia-pushkina [17]

Answer:

The value is  y  =  0.00732 \ m    

Explanation:

From the question we are told that

    The wavelength of each source is  \lambda  = 720 \ nm =  720 *10^{-9} \  m

     The distance from the pinhole D = 10 \ m

     The diameter is d =  1.2 mm = \frac{1.2}{1000} = 0.0012 \ m

Generally from Rayleigh's criterion  we have that the distance between the sources of light for their diffraction patterns is mathematically represented as '

        y  =  \frac{ 1.22 *  \lambda *  D}{d}

=>      y  =  \frac{ 1.22 * 720 *10^{-9}*   10 }{ 0.0012}

=>      y  =  0.00732 \ m      

6 0
3 years ago
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