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Alecsey [184]
4 years ago
6

A battery does work on electric charges to bring them to a position of higher electric potential energy so that they can flow th

rough a circuit to a lower potential energy. the potential difference between the terminals of a battery, when no current flows to an external circuit, is referred to as the terminal voltage. the internal resistance of a battery decreases with decreasing temperature. a battery is a device that produces electricity by transforming chemical energy into electrical energy.\
Physics
1 answer:
Ipatiy [6.2K]4 years ago
7 0
(Missing question is: which of the following statements are true?)

a) <span>A battery does work on electric charges to bring them to a position of higher electric potential energy so that they can flow through a circuit to a lower potential energy --> TRUE
That's true: the battery does the work to move the charges to one end of its terminal thus creating a potential difference between the two terminals. Then, when it is connected to the circuit, charges start to flow to the terminal at lower potential (through the circuit)

b) </span><span>the potential difference between the terminals of a battery, when no current flows to an external circuit, is referred to as the terminal voltage --> FALSE
This is false: when no current flows, it is called e.m.f. (electromotive force)

c) </span><span>the internal resistance of a battery decreases with decreasing temperature 
--> TRUE
In fact, the dependence of a resistance with the temperature is:
</span>R=R_0[1+\alpha (T-T_0)]
with \alpha being generally positive, therefore the value of the resistance is proportional to T, and when T decreases, R decreases as well.

<span>d) a battery is a device that produces electricity by transforming chemical energy into electrical energy --> TRUE
</span><span>That's true: a battery uses chemical reactions to create a potential difference between the two terminals that can be exploited to make charges flowing through a circuit.


</span>
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<h2>Answer:</h2>

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<h2>Explanation:</h2>

At constant volume, the pressure (P) of an ideal gas is directly proportional to its temperature (T) as stated by Joseph Gay-Lussac. i.e

P ∝ T

=> P = KT

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=> (P₁ / T₁) = (P₂ / T₂) = K

=> (P₁ / P₂) = (T₁ / T₂) = K        

=> (P₂ / P₁) = (T₂ / T₁) = K         -----------------------(i)

Where;

P₁ and P₂ are the initial and final pressures of the gas.

T₁ and T₂ are the initial and final temperatures of the gas.

(a) if temperature rises from 39 to 78 K;

This implies that;

T₁ = 39 K

T₂ = 78 K

Substitute these values into equation (i) as follows;

=> (P₂ / P₁) = (78 / 39)

=> (P₂ / P₁) = (26 / 13)

=> (P₂ / P₁) = (2 / 1)

Therefore, the ratio P₂ / P₁ = 2 / 1

(b) if temperature rises from 39.0 to 53.8 K;

This implies that;

T₁ = 39.0 K

T₂ = 53.8 K

Substitute these values into equation (i) as follows;

=> (P₂ / P₁) = (53.8 / 39)

=> (P₂ / P₁) = (17.93 / 13)

Therefore, the ratio P₂ / P₁ = 17.93 / 13

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