A 513 g ball strikes a wall at 14.7 m/s and rebounds at 11.3 m/s. The ball is in contact with the wall for 0.038 s. What is the

Question

3 years ago

9

magnitude of the average force acting on the ball during the collision? Answer in units of N.

1 answer:

Natasha_Volkova [10] · Answer 1 · 2022-04-08T22:00:56+03:00

consider the velocity of the ball towards the wall as negative and away from the wall as positive.

m = mass of the ball = 513 g = 0.513 kg

v₀ = initial velocity of the ball towards the wall before collision = - 14.7 m/s

v = final velocity of the ball away from the wall after collision = 11.3 m/s

t = time of contact with the wall = 0.038 sec

F = average force acting on the ball

using impulse-change in momentum equation , average force is given as

F = m (v - v₀)/t

inserting the values

F = (0.513) (11.3 - (- 14.7))/0.038

F = 351 N