Answer:
Mass =41.36 g
Explanation:
Given data:
Mass of CH₄ = 15 g
Mass of O₂ = 114 g
Mass of CO₂ produced = ?
Solution:
Chemical equation:
CH₄ + 2O₂ → CO₂ + 2H₂O
Number of moles of CH₄:
Number of moles = mass/ molar mass
Number of moles = 15 g /16 g/mol
Number of moles = 0.94 mol
Number of moles of O₂:
Number of moles = mass/ molar mass
Number of moles = 114 g /32 g/mol
Number of moles = 3.6 mol
Now we will compare the moles of CO₂ with both reactant.
O₂ : CO₂
2 : 1
3.6 : 1/2×3.6= 1.8 mol
CH₄ : CO₂
1 : 1
0.94 : 0.94
Number of moles of CO₂ produced by CH₄ are less so it will limiting reactant.
Mass of CO₂:
Mass = number of moles × molar mass
Mass = 0.94 mol × 44 g/mol
Mass =41.36 g
