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Klio2033 [76]
3 years ago
11

A student of mass 51 kg wants to walkbeyond the edge of a cliff on a heavy beam ofmass 220 kg and length 11 m. The beam isnot at

tached to the cliff in any way, it simplylies on the horizontal surface of the clifftop,with one end sticking out beyond the cliff’sedgeHow far from the edge of the ledge can the beam extend if it sticks out as far as possible beyond the edge, but the student can walk to the beam’s end without falling down? Answer in units of m.
Physics
1 answer:
pishuonlain [190]3 years ago
3 0

Answer:

4.465 m

Explanation:

Taken the beam to be uniform, then the center of gravity will act at the mid-point of the beam. The mid point = 11 / 2 = 5.5 m

since the boy can walk to the end of the beam without falling,

then the torque ( moment of the force) by beam = torque by students at the end of the beam

let the distance of the boy = x

220 ( 5.5 - x ) = 51 × x

1210 - 220 x = 51 x

1210 = 51 x + 220 x

1210 = 271 x

x = 1210 / 271 = 4.465 m

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The three characteristics of a good scientist are his curiosity, creativity and problem-solving skills.

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2 years ago
What were Rosalind Franklin, James Watson, and Francis Crick’s discovery, and what did it lead to? In three to five sentences, e
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8 0
1 year ago
A box is held at rest by two ropes that form 30° angles with the vertical. The tension T in either rope is 42 N. What is the wei
iragen [17]
<h3><u>Answer;</u></h3>

= 73 N

<h3><u>Explanation</u>;</h3>

Using the formula

2 T cos(30°) = w

Where; T is the tension on each string, while w is the weight of the box given by mg

Therefore;

W = 2Tcos 30°

    = 2 × 42 cos 30°

    = 84 cos 30°

    = 72.74

<u>   ≈ 73 N</u>

7 0
3 years ago
Calculate the pressure on the ground from an 80 kg woman leaning on the back of one of her shoes with a 1cm diameter heel, and c
rodikova [14]

Answer:

Pressure of woman will be 99.87\times 10^5N/m^2

Pressure of the elephant will be 1716560.50N/m^2

Explanation:

We have given that mass of the woman m = 80 kg

Acceleration due to gravity g=9.8m/sec^2

Diameter of shoes = 1 cm =0.01 m

So radius r=\frac{d}{2}=\frac{0.01}{2}=0.005m

So area A=\pi r^2=3.14\times 0.005^2=7.85\times 10^{-5}m^2

We know that force is given  F = mg

So F=80\times 9.8=784N

Now we know that pressure is given by P=\frac{F}{A}=\frac{784}{7.85\times 10^{-5}}=99.87\times 10^5N/m^2

Now mass of elephant m = 5500 kg

So force of elephant = 5500×9.8 = 53900 N

Diameter = 20 cm

So radius r = 10 cm

So area will be A=3.14\times 0.1^2=0.0314m^2

So pressure will be P=\frac{53900}{0.0314}=1716560.50N/m^2

3 0
3 years ago
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