Answer:
Fe
Explanation:
<em>Ferrum</em><em> </em>[Iron] has the most stable nucleus because of <em>binding</em><em> </em><em>energy</em><em> </em><em>per</em><em> </em><em>nucleon</em><em>.</em><em> </em>Although Uranium<em> </em>is<em> </em>another possibility, in this case, it is more radioactive than Iron. It disintegrates very swiftly that all is done so, just to achieve stability.
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Answer:
molecule. The smallest part of a compound is the molecule. A molecule retains all the properties of that compound.
Explanation:
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b. Analysis. In the analysis step, you organize and interpret your data to see if they support your hypothesis.
a. Experimentation is <em>incorrect</em> because this is the step in which you do experiments to test if your prediction is accurate.
c. Conclusion is <em>incorrect</em> because a conclusion is a decision you make to accept or reject your hypothesis.
d. Hypothesis is <em>incorrect</em> because a hypothesis is a proposed explanation for why something happens.
Answer:
Explanation:
13 ) symbol of enthalpy change = Δ H .
14 ) enthalpy change is nothing but heat absorbed or evolved .
During fusion enthalpy change
Δ H .= m Lf , m is mass and Ls is latent heat of fusion
During evaporation, enthalpy change
Δ H .= m Lv , m is mass and Lv is latent heat of evaporation
during temperature rise , enthalpy change
Δ H = m c Δ T
In case of gas , enthalpy change can be calculated by the following relation
Δ H = Δ E + W , Δ E is change in internal energy , W is work done by gas.
15 ) When enthalpy change is negative , that means heat is released to the environment .So reaction is called exothermic .
when heat is absorbed enthalpy change is positive . Reaction is endothermic.
From the calculation, the standard free energy of the system is -359kJ.
<h3>What is the standard free-energy?</h3>
The standard free-energy is the energy present in the system. We have to first obtain the cell potential using the formula;
Ereduction - E oxidation = 0.96 V - 0.34 V = 0.62 V
Using the formula;
ΔG = -nFEcell
ΔG =-(6 * 96500 * 0.62)
ΔG =-359kJ
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