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3 years ago

HELPPP What method should you use to separate this sample of mixture?

Chemistry

1 answer:

kozerog [31]3 years ago

8 0

Answer:

The answer to your question is: D. Fractional distillation

Explanation:

A. Column chromatography this method is use to separate mixtures base in its capacity to be absorbed.

B. Fractional crystallization this method use the solubility of solutes in a solvent.

C. Simple distillation is a method to separate 2 liquids based on the difference in their boiling points.

D. Fractional distillation is a method used to separate a mixture of liquids which have their boiling points very close.

E. Paper chromatography is a method to separate a mixture based on their different rate of migration on a paper.

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A metal is found that has a mass of 27g and will displace 6mL of water. Calculate its density and identify the metal.

melisa1 [442]

The density of metal = 4.5 g/ml, and the metal = Titanium

<h3>Further explanation </h3>

Density is a quantity derived from the mass and volume

Density is the ratio of mass per unit volume

Density formula:

$\large {\boxed {\bold {\rho ~ = ~ \frac {m} {V}}}}$

ρ = density

m = mass

v = volume

mass of metal=27 g

volume = 6 ml

The density :

$\tt \rho=\dfrac{27}{6}\\\\\rho=4.5~g/ml$

The metal with a density of 4.5 g/ml is Titanium

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2 years ago

What is the mass of 1.88 mol Na

Rina8888 [55]

The answer to your question:

1.88 moles Na is 43.22 grams

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In the reaction of sodium with oxygen

Anestetic [448]

Answer:

I think that it's b

Explanation:

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For the following reaction, 22.9 grams of nitrogen monoxide are allowed to react with 5.80 grams of hydrogen gas. nitrogen monox

ololo11 [35]

Answer:

1) Maximun ammount of nitrogen gas: $m_{N2}=10.682 g N_2$

2) Limiting reagent: $NO$

3) Ammount of excess reagent: $m_{N2}=4.274 g$

Explanation:

<u>The reaction </u>

$2 NO (g) + 2 H_2 (g) \longrightarrow N_2 (g) + 2 H_2O (g)$

Moles of nitrogen monoxide

Molecular weight: $M_{NO}=30 g/mol$

$n_{NO}=\frac{m_{NO}}{M_{NO}}$

$n_{NO}=\frac{22.9 g}{30 g/mol}=0.763 mol$

Moles of hydrogen

Molecular weight: $M_{H2}=2 g/mol$

$n_{H2}=\frac{m_{H2}}{M_{H2}}$

$n_{H2}=\frac{.5.8 g}{2 g/mol}=2.9 mol$

Mol rate of H2 and NO is 1:1 => hydrogen gas is in excess

1) <u>Maximun ammount of nitrogen gas</u> => when all NO reacted

$m_{N2}=0.763 mol NO* \frac{1 mol N_2}{2 mol NO}*\frac{28 g N_2}{mol N_2}$

$m_{N2}=10.682 g N_2$

2) <u>Limiting reagent</u>: $NO$

3) <u>Ammount of excess reagent</u>:

$m_{N2}=(2.9 mol - 0.763 mol NO* \frac{1 mol H_2}{1 mol NO})*\frac{2 g H_2}{mol H_2}$

$m_{N2}=4.274 g$

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3 years ago

What is the volume of 0.2 moles of neon gas at STP?

eduard

Standard Molar Volume is the volume occupied by one mole of any gas at STP. Remember that "STP" is Standard Temperature and Pressure. Standard temperature is 0 &176:C or 273 K. Standard pressure is 1 atmosphere or 760 mm Hg (also called "torr"). 1 mole of any gas at STP occupies 22.4 liters of volume.

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