Question

Estimate the magnitude of the electric field due to the proton in a hydrogen atom at a distance of 5.29 x 10-11 m, the expected position of the electron in the atom.
a) 1012 N/C
b) 10-11 NIC
c) 106 N/C
d) 1014 N/C
e) 108 N/C

Answer 1

Would be A 1012 N/C because The magnitude of the electric field at distance r from a point charge q is E=k
e
​
q/r
2
, so
E=
(5.11×10
−11
m)
2

(8.99×10
9
N.m
2
/C
2
)(1.60×10
−19
C)
​

=5.51×10
11
N/C∼10
1
2N/C
making (e) the best choice for this question.