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3 years ago

7

Which Equation will you use to solve this question (use the chart at the end of the lesson) While skiing, Sam flies down a hill

and hits a jump. He has a mass of 75 kg, and he leaves the jump at 18 m/s. What is his momentum as he leaves the jump?
A.Momentum Equation

B.Impulse Equation

C.Collision Equation Inelastic

D. Collision Equation Elastic

2 answers:

alekssr [168]3 years ago

8 0

I think is B....hope this helps

ozzi3 years ago

4 0

A.Momentum Equation

m = mass = 75 kg

v = velocity = 18 m/s

P = momentum

Using the momentum equation , momentum is given as

P = mv

P = 75 x 18

P = 1350 kgm/s

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The successive ionization energies for an unknown element are listed below. To which family in the periodic table does the unkno

bagirrra123 [75]

<span>The jump from 1966 to 16347 is the largest one or simply we can say it is hard to lose the 3rd electron.Whereas, it is relatively easy to lose the first two electrons.

So there will be only 2 electrons in the outer most shell.

According to the information mentioned above we can conclude the </span><span>unknown element likely belongs to the second group.
</span><span>I2 = 1752 kj/mol</span>

4 0

2 years ago

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Write the resistivity of gold, iron ,Mercury, silver,copper? which is bad conductor?

Tamiku [17]

Answer:

Mercury is a bad conductor of heat but a fair conductor of electricity

By the way PURE SILVER is the best conductor of electricity

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2 years ago

Choose the correct association for: dense bushes<br><br> savanna<br> rain forest or jungle

Gemiola [76]

Answer:

Climate is determined by averaging the seasonal weather conditions for a region over a period of many ______ years

Choose the correct association for: dense bushes rain forest or jungle

Choose the correct association for: plains savanna

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2 years ago

Normal atmospheric pressure is 1.013 105 Pa. The approach of a storm causes the height of a mercury barometer to drop by 27.1 mm

Burka [1]

Answer:

The atmospheric pressure is $0.97622\times10^{5}\ Pa$ .

Explanation:

Given that,

Atmospheric pressure $P_{atm}= 1.013\times10^{5}\ Pa$

drop height h'= 27.1 mm

Density of mercury $\rho= 13.59 g/cm^3$

We need to calculate the height

Using formula of pressure

$p = \rho g h$

Put the value into the formula

$1.013\times10^{5}=13.59\times10^{3}\times9.8\times h$

$h =\dfrac{1.013\times10^{5}}{13.59\times10^{3}\times9.8}$

$h=0.76\ m$

We need to calculate the new height

$h''=h - h'$

$h''=0.76-27.1\times10^{-3}$

$h''=0.76-0.027$

$h''=0.733\ m$

We need to calculate the atmospheric pressure

Using formula of atmospheric pressure

$P=\rho g h$

Put the value into the formula

$P= 13.59\times10^{3}\times9.8\times0.733$

$P=0.97622\times10^{5}\ Pa$

Hence, The atmospheric pressure is $0.97622\times10^{5}\ Pa$ .

7 0

2 years ago

Two loudspeakers in a 20c room emit 686 hz sound waves along the x-axis.a. if the speakers are in phase, what is the smallest di

jeyben [28]

<u>Answer :</u>

(a) d = 0.25 m

(b) d = 0.5 m

<u>Explanation :</u>

It is given that,

Frequency of sound waves, f = 686 Hz

Speed of sound wave at $20^0\ C$ is, v = 343 m/s

(1) Perfectly destructive interference occurs when the path difference is half integral multiple of wavelength i.e.

$d=\dfrac{\lambda}{2}$ ........(1)

Velocity of sound wave is given by :

$v=f\times \lambda$

$d=\dfrac{v}{2f}$

$d=\dfrac{343\ m/s}{2\times 686\ Hz}$

$d=0.25\ m$

Hence, when the speakers are in phase the smallest distance between the speakers for which the interference of the sound waves is perfectly destructive is 0.25 m.

(2) For constructive interference, the path difference is integral multiple of wavelengths i.e.

$d=n\lambda$ ( n = integers )

Let n = 1

So, $d=\dfrac{v}{f}$

$d=\dfrac{343\ m/s}{686\ Hz}$

$d=0.5\ m$

Hence, the smallest distance between the speakers for which the interference of the sound waves is maximum constructive is 0.5 m.

4 0

3 years ago

Read 2 more answers