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Aleks [24]
1 year ago
9

Create a Graph : Include numbers, axes, and order pairs

Physics
1 answer:
dlinn [17]1 year ago
6 0
Answer:

a) Peak value = 20

b) Average value = 9.0

c) RMS value = 14.15

Explanation:

The peak-to-peak value = 40

v_{p-p}=40\begin{gathered} v_{p-p}=2v_p \\  \\ 40=2v_p \\  \\ v_p=\frac{40}{2} \\  \\ v_p=20 \end{gathered}

c) The rms value

\begin{gathered} v_{rms}=\frac{v_p}{\sqrt{2}} \\  \\ v_{rms}=\frac{20}{\sqrt{2}} \\  \\ v_{rms}=14.14 \end{gathered}

b) Average value over alternation of the sine wave

\begin{gathered} v_{avg}=0.637v_p \\  \\ v_{avg}=0.637\times14.14 \\  \\ v_{avg}=9.0 \end{gathered}

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Plants make food through photosynthesis, and photosynthesis takes place mostly in plant leaves, but when plants lose their leave
Nastasia [14]

Answer:

The answer is not B or D because they need light co2 and water to make their food so B and D are out. and unless someone is walking during winter to feed it. It will not be A so the answer is C.

Explanation:

3 0
3 years ago
How many atoms are there in 3.4moles if helium ,show the calculation
prohojiy [21]
Answer: 20.4752789138x x  10^23 atoms
To count how many atoms in moles you need to know Avogadro's number. Avogadro's number dictate that for every mole there is 6.022140857 × 10^23 molecule/atoms.
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6 0
3 years ago
At a certain instant a particle is moving in the +x direction with momentum +8 kg m/s. During the next 0.13 seconds a constant f
jeka94

Answer:

The momentum of the particle at the end of the 0.13 s time interval is 7.12 kg m/s

Explanation:

The momentum of the particle is related to force by the following equation:

Δp = F · Δt

Where:

Δp =  change in momentum = final momentum - initial momentum

F = constant force.

Δt = time interval.

Let´s calculate the x-component of the momentum after the 0.13 s:

final momentum - 8 kg m/s = -7 N · 0.13 s

final momentum = -7 kg m/s² · 0.13 s + 8 kg m/s

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Now let´s calculate the y-component of the momentum vector after the 0.13 s. Since the particle wasn´t moving in the y-direction, the initial momentum in this direction is zero:

final momentum = 5 kg m/s² · 0.13 s

final momentum = 0.65 kg m/s

Then, the mometum vector will be as follows:

p = (7.09 kg m/s,  0.65 kg m/s)

The magnitude of this vector is calculated as follows:

|p| = \sqrt{(7.09 kg m/s)^{2} + (0.65 kg m/s)^{2}} = 7.12 kg m/s

The momentum of the particle at the end of the 0.13 s time interval is 7.12 kg m/s

4 0
3 years ago
Can tectonic plates switch places with other tectonic plates, Im generally curious
Bingel [31]

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4 0
3 years ago
Read 2 more answers
Calculate the conductance of a conduit the cross-sectional area of which is 3.0 cm2 and the length of which is 9.0 cm, given tha
pshichka [43]
For resistance we have R=ρ l/a
 thus for conductance we have K=σ a/l
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σ = .80 Ω-1 cm-1
l =9 cm
a = 3 cm²
K=.80 ×3/9
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6 0
3 years ago
Read 2 more answers
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