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mezya [45]
3 years ago
7

On the first day camping, a group hiked at a rate of 2 1/4 miles per hour for 2 1/2 hours before taking a break. How many miles

had the group hiked before the break?
Mathematics
2 answers:
scoray [572]3 years ago
5 0

Answer: 5 5/8 miles

Step-by-step explanation:

First turn 2 1/4 into an improper fraction

2 x 4 = 8 + 1 = 9

9/4

Now turn 2 1/2 into an improper fraction

2 x 2 = 4 + 1 = 5

5/2

Now multiply

9/4 x 5/2 = 45/8

5 5/8 miles

DaniilM [7]3 years ago
4 0

First, use the distributive property and split 2 off from 1/2 in the hours category.

(2) (1/2)

Next, multiply 2 1/4 times 2, the first integer in the distributive equation.

2 1/4*2 = 4 1/2

For now, put 4 1/2 aside.

Then, multiply 2 1/4 by 1/2.

2 1/4*1/2 = 1 1/8

Now, add the two products together

4 1/2 + 1 1/8 = 5 5/8

Answer is 5 and 5/8

Hope this helps!

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Answer:

165 liters of 15% solution

Step-by-step explanation:

15F + 65S = 60(1650)

F + S = 1650

F = 1650-S

15(1650-S) +65S = 99000

50S = 99000-24750= 74250

S = 74250/50 = 7425/5 = 1485 liters of 65% solution

F = 1650-1485 = 165 liters of 15% solution

65 is much closer to 60 than 15 is,  so you know there will be mostly 65% solution with relatively little 15%

Hope this helps, have a nice day/night! :D

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36.

Step-by-step explanation:

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The probability that your call to a service line is answered in less than 30 seconds is 0.75. Assume that your calls are indepen
vfiekz [6]

Answer:

a) 0.2581

b) 0.4148

c) 17

Step-by-step explanation:

For each call, there are only two possible outcomes. Either they are answered in less than 30 seconds. Or they are not. The probabilities for each call are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

p = 0.75

a. If you call 12 times, what is the probability that exactly 9 of your calls are answered within 30 seconds? Round your answer to four decimal places (e.g. 98.7654).

This is P(X = 9) when n = 12. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 9) = C_{12,9}.(0.75)^{9}.(0.25)^{3} = 0.2581

b. If you call 20 times, what is the probability that at least 16 calls are answered in less than 30 seconds? Round your answer to four decimal places (e.g. 98.7654).

This is P(X \geq 16) when n = 20

So

P(X \geq 16) = P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 16) = C_{20,16}.(0.75)^{16}.(0.25)^{4} = 0.1897

P(X = 17) = C_{20,17}.(0.75)^{17}.(0.25)^{3} = 0.1339

P(X = 18) = C_{20,18}.(0.75)^{18}.(0.25)^{2} = 0.0669

P(X = 19) = C_{20,19}.(0.75)^{19}.(0.25)^{1} = 0.0211

P(X = 20) = C_{20,20}.(0.75)^{20}.(0.25)^{0} = 0.0032

So

P(X \geq 16) = P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20) = 0.1897 + 0.1339 + 0.0669 + 0.0211 + 0.0032 = 0.4148

c. If you call 22 times, what is the mean number of calls that are answered in less than 30 seconds? Round your answer to the nearest integer.

The expected value of the binomial distribution is:

E(X) = np

In this question, we have n = 22

So

E(X) = 22*0.75 = 16.5

The closest integer to 16.5 is 17.

7 0
3 years ago
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