Answer:
F = 2 * 30 / 5 = 12 N to stop forward motion
F = 2 * 40 / 5 = 16 N to accelerate to 90 degrees
(12^2 + 16^2)^1.2 = 20 N average force applied
Okay so don't quote me on this but I believe the answer is A) I'm saying this because B and C make no sense. and you can't change the mass of something without changing it totally.
Answer: 1477.78 N
Explanation:
Let's assume that the cross sectional area of the smaller piston be A1
let's also assume the cross sectional area of the larger piston be A2
We assume the force applied to the smaller piston be F1
We also assume the force applied to the larger piston be F2
we then use the formula
F1/A1 = F2/A2
From our question,
The radius of the smaller piston is 5 cm = 0.05 m
The radius of the larger piston is 15 cm = 0.15 m
The force of the larger piston is 13300 N
The force of the smaller piston is unknown = F
A1 = πr² = 3.142 * 0.05² = 0.007855 m²
A2 = πr² = 3.142 * 0.15² = 0.070695 m²
F1/0.007855 = 13300/0.070695
F1 = (13300 * 0.007855) / 0.070695
F1 = 104.4715 / 0.070695
F1 = 1477.78 N
Thus, the force the compressed air must exert is 1477.78 N
To answer, we determine the velocity of the flea when it leaves the ground. Using the given value for distance, the velocity can be determined through the equation,
2a d = (Vf)² - (Vi)²
where a is the acceleration due to gravity, d is distance, Vf is the final velocity which is equal to zero and Vi is the initial velocity. Substituting the known values,
2(9.8 m/s²)(40cm/100cm) = (Vi)²
The value of Vi from the equation is 2.8 m/s.
The equation for determining the kinetic energy is:
KE = 0.5mv²
Substituting,
KE = 0.5(0.60 x 10^-3g)(1 kg/1000g)(2.8 m/s)²
KE = 2.352 x 10^-6 J
Answer:
False, When an object rolls over a surface, the kind of friction that occurs is called <em><u>ROLLING FRICTION</u></em>
Explanation:
