Answer:
Flow rate 2.34 m3/s
Diameter 0.754 m
Explanation:
Assuming steady flow, the volume flow rate along the pipe will always be constant, and equals to the product of flow speed and cross-section area.
The area at the well head is
![A = \pi r_w^2 = \pi (0.509/2)^2 = 0.203 m^2](https://tex.z-dn.net/?f=A%20%3D%20%5Cpi%20r_w%5E2%20%3D%20%5Cpi%20%280.509%2F2%29%5E2%20%3D%200.203%20m%5E2)
So the volume flow rate along the pipe is
![\dot{V} = Av = 0.203 * 11.5 = 2.34 m^3/s](https://tex.z-dn.net/?f=%5Cdot%7BV%7D%20%3D%20Av%20%3D%200.203%20%2A%2011.5%20%3D%202.34%20m%5E3%2Fs)
We can use the similar logic to find the cross-section area at the refinery
![A_r = \dot{V}/v_r = 2.34 / 5.25 = 0.446 m^2](https://tex.z-dn.net/?f=A_r%20%3D%20%5Cdot%7BV%7D%2Fv_r%20%3D%202.34%20%2F%205.25%20%3D%200.446%20m%5E2)
The radius of the pipe at the refinery is:
![A_r = \pi r^2](https://tex.z-dn.net/?f=A_r%20%3D%20%5Cpi%20r%5E2)
![r^2 =A_r/\pi = 0.446/\pi = 0.141](https://tex.z-dn.net/?f=r%5E2%20%3DA_r%2F%5Cpi%20%3D%200.446%2F%5Cpi%20%3D%200.141)
![r = \sqrt{0.141} = 0.377m](https://tex.z-dn.net/?f=r%20%3D%20%5Csqrt%7B0.141%7D%20%3D%200.377m)
So the diameter is twice the radius = 0.38*2 = 0.754m
Mass is measured in kg
Velocity is measured in ms^-1
Hope this is what you were looking for
Answer: B ≈ Credit unions are owned by stockholders rather than partners
That's really going to depend on ...
-- where point-c is
and
-- the cyclist's mass
and
-- the acceleration of gravity on the planet where the hill is
The work needed if a force of 3N is used to move a table 25 metres is 75Nm (joules).
<h3>How to calculate work done?</h3>
Work is a measure of energy expended in moving an object. This means that no work is done if the object does not move.
Force is a physical quantity that denotes the ability to push, pull, twist or accelerate a body and which has a direction and is measured in Newtons.
Work done on an object can be calculated by multiplying the force applied to move the object by the distance the object moves as follows:
Work done = Force (N) × distance (m)
According to this question, a force of 3 Newtons is used to move a table over a distance of 25 meters. The work done on the table can be calculated as follows;
W = 3N × 25metres
W = 75Nm
Therefore, 75Nm is the work done on the table.
Learn more about work done at: brainly.com/question/2117638
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