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bearhunter [10]
3 years ago
5

4-Methylphenol, CH3C6H4OH (pKa 10.26), is only slightly soluble in water, but its sodium salt, CH3C6H4O-Na , is quite soluble in

water. Describe the solubility of 4-methylphenol in solutions of sodium hydroxide, sodium bicarbonate (NaHCO3), and sodium carbonate (Na2CO3). The pKa values for the conjugate acids of sodium hydroxide, sodium bicarbonate (NaHCO3), and sodium carbonate (Na2CO3) are 15.7, 6.36, and 10.33, respectively.
Chemistry
1 answer:
Vinil7 [7]3 years ago
4 0

Explanation:

We know that more is the pK_{a} value, weaker will be the acid. Also, an acid completely dissociates into ions in an aqueous base solution when pK_{a} of conjugate acid of base is greater than acid.

4-methylphenol (CH_{3}C_{6}H_{4}OH) (pK_{a} = 10.26) is quite soluble in its sodium salt. In NaOH, the dissociation will be as Na^{+} and OH^{-} ions as NaOH is a strong base.

Therefore, 4-methylphenol will readily dissolve in NaOH solution.

As, NaHCO_{3} is not a strong base but as 4-Methylphenol forms a sodium salt hence, it will have a low solubility as compared to NaOH.

Whereas Na_{2}CO_{3} is not a base but when dissolved in water it shows basic character as it produces NaOH (strong base) and H_{2}CO_{3} (weak acid). As a result, the solution gets basic. Hence, 4-methylphenol will readily dissolve in Na_{2}CO_{3}.

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