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Gwar [14]
3 years ago
15

How much electrical energy is used by a 75 W laptop that is operating 12 minutes?

Physics
1 answer:
LiRa [457]3 years ago
4 0
75 watts means 75 joules per second. 12 minutes is (12 x 60) = 720 seconds. 75 j/sec x 720sec = 54,000 joules.
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Classify each possible hypothesis about a medicinal aloe vera plant as falsifiable or non-falsifiable.
pychu [463]

Answer:

Aloe vera is a succulent plant species ( with fleshy water storing tissue) belonging to the genus Aloe.

It is used in many products ( including beverages, cosmetic products as gel, medicinal ointments). Its juice is quite bitter in taste. It is known to be the best skin moisturizer and can be used for healing wounds by enhancing the renewal of damaged cells. It is also used as an anticarcinogen, thus reduces the chances of cancer.

Thus, the given hypothesis can be classified as  falsifiable ( which is proven wrong) or non-falsifiable ( which is proven right) in the following way-

Falsifiable-

Aloe vera juice tastes  better than carrot juice.

Non Falsifiable-

Aloe vera gel is the best  natural skin moisturizer.

Aloe vera gel can heal  wounds by boosting  cell renewal.

Drinking aloe juice can  reduce the risk of lung  cancer.

7 0
3 years ago
A third wire of the same material has the same length and twice the diameter as the first. How far will it be stretched by the s
leonid [27]

Complete question is;

A force stretches a wire by 0.60 mm. A second wire of the same material has the same cross section and twice the length.

a) How far will it be stretched by the same force?

b) A third wire of the same material has the same length and twice the diameter as the first. How far will it be stretched by the same force?

Answer:

0.15 mm

Explanation:

According to Hooke's Law,

E = Stress(σ)/Strain(ε)

Where E is youngs modulus

Formula for stress is;

Stress(σ) = Force(F)/Area(A)

Formula for strain is;

Strain(ε) = Change in length/original length = (Lf - Li)/Li

We are also told that a second wire of the same material has the same cross section and twice the length.

Thus;

Rearranging Hooke's Law to get the constants on one side, we have;

F/(AE) = ε

Thus from the conditions given;

ε1 = 0.6/Li

ε2 = (Change in length)/(2*Li)

And ε1 = ε2

Thus;

0.6/Li = Change in length/(2*Li)

Li will cancel out and we now have;

Change in length = 2 × 0.6 = 1.2 mm

Finally, we are told A third wire of the same material has the same length and twice the diameter as the first.

Area of a circle;A1 = πd²/4

Now, we are told d is doubled.

Thus, new area of the new circle is;

A2 = π(2d)²/4 = πd²

Rearranging Hooke's Law,we have;

F/A = εE

Since F and E are now constants, we have;

F/E = constant = Aε

Thus;

A1(ε1) = A2(ε2)

A1 = πd²/4

e1 = 0.60/Li

A2 = πd²

e2 = Change in length/Li

Thus;

((πd²/4) × 0.6)/Li = (πd² × Change in length)/ Li

Rearranging, Li and πd² will cancel out to give;

0.6/4 = Change in length

Change in length = 0.15 mm

4 0
2 years ago
Which do you think will penetrate farther into a block of lead, x-rays, or gamma rays
disa [49]
Gamma rays because it has more penetrating power and frequency but shorter wavelength.
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3 years ago
The forces acting on this object are _______ and the net force is ________ Balanced, 0 N Balanced, 10 N Unbalanced, 10 N Unbalan
Amanda [17]
1st Blank Answer: Balanced   
2nd Blank Answer: 0n 

I took the test and got it right
I would appreciate a Brainliest...
5 0
2 years ago
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irga5000 [103]

Answer:

Refer to the attachment.

7 0
2 years ago
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