At the time that I'll call ' Q ', the height of the stone that was
dropped from the tower is
H = 50 - (1/2 G Q²) ,
and the height of the stone that was tossed straight up
from the ground is
H = 20Q - (1/2 G Q²) .
The stones meet when them's heights are equal,
so that's the time when
<span>50 - (1/2 G Q²) = 20Q - (1/2 G Q²) .
This is looking like it's going to be easy.
Add </span><span>(1/2 G Q²) to each side.
Then it says
50 = 20Q
Divide each side by 20: 2.5 = Q .
And there we are. The stones pass each other
2.5 seconds
after they are simultaneously launched.
</span>
Your weight on the moon given the data from the question is 110.5 N
<h3>Definition of mass and weight </h3>
Mass is simply defined as the quantity of matter present in an object. The mass of an object is constant irrespective of the location of the object.
Weight is simply defined as the gravitational pull on an object. The weight of an object varies from place to place due to gravity.
<h3>Relationship between mass and weight </h3>
Mass and weight are related according to the following equation
Weight (W) = mass (m) × Acceleration due to gravity (g)
<h3>How to determine the weight on the moon</h3>
- Mass (m) = 65 Kg
- Acceleration due to gravity on the moon (g) = 1.7 m/s²
- Weight (W) =?
W = mg
W = 65 × 1.7
W = 110.5 N
Learn more about mass and weight:
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-reflection and refraction of light
-dispersion of light
-absorption of light
-polarization of light
One advantage is that whatever resource it is, it will never run out and you wont have to worry about not having it. A second is that there is going to be enough for everyone to use however much they want without there having to be a limit on how much you use.
Answer:
Final mass=0.89kg
Final pressure=5.6bar
Explanation:
To find mass,m=v/v1
But v1=vf + x(vg-vf)
Vf= 0.001093m^3/kg
Vg= 0.3748m^3/kg
V1= 0.001093+0.5(0.3748-0.001093)
V1= 0.225m^3/kg
M= 0.20/0.225 =0.89kg
Final pressure will be:
V/V1= P/P1
Cross multiply
VP1=V1P
P1= 0.225×5/0.2
P1=:5.6 bar
