The balanced chemical reaction is:
HC2H3O2<span> (aq) +Ba(OH)2 (aq) --> H2O (l) +Ba(C2H3O2)2
</span>
We are given the amount of HC2H3O2 to be used in the reaction. We use this amount as the starting point of our calculations.
0.432 mol HC2H3O2 ( 1 mol Ba(OH)2 / 1 mol HC2H3O2 ) = 0.432 mol Ba(OH)2 needed
Hope this answers the question.
Answer:
<em>C</em> H2SO4 = 9.79 M
Explanation:
- molarity (M) ≡ # dissolved species / V sln
- H2SO4 ↔ H3O+ + SO4-
∴ %w/w H2SO4 = 960% = g H2SO4 / g sln * 100
⇒ 9.6 = g H2SO4 / g sln
calculation base: 1000 g sln
⇒ g H2SO4 = 9600g
⇒<em> </em>mol<em> </em>H2SO4 =<em> </em>9600 g H2SO4 * ( mol H2SO4/ 980g H2SO4 ) = 9.796 mol H2SO4
⇒ V sln = 1000g sln / 1000g/L = 1 L sln
∴ ρ H20 ≅ 1000 Kg/m³ = 1000 g/L
⇒ <em>C</em> H2SO4 = 9.796 mol H2SO4 / 1 L sln
⇒ <em>C</em> H2SO4 = 9.796 M
The answer is 1.6 atm. Let's first calculate the mole fraction of gas Y.
The mole fraction (x) is: x = n1/n, where n1 is a number of moles of an
individual gas in a mixture and n is total moles of the gas mixture. We
know that n1 of gas Y is 6.0 mol (n1 = 6.0 mol) and that there are in
total 8. mol of the gas mixture (n = 2.0 + 6.0 = 8.0 mol). Now calculate
the mole fraction of gas Y. x = 6.0/8.0 = 0.75. Now, let's use the mole
fraction of gas Y (x) and the total pressure (P) to calculate the
partial pressure of gas Y (P1): x = P1/P. P1 = x * P. If x = 0.75 and P =
2.1 atm, then the partial pressure of gas Y is: P1 = 0.75 * 2.1 atm =
1.6 atm.
The ZnCl₂ solution have a molarity of 1.33 M.
Explanation:
We have the following chemical reaction:
Zn (s) + CuCl₂ (aq) → ZnCl₂ (aq) + Cu (s)
number of moles = mass / molar weight
number of moles of Zn = 25 / 65.4 = 0.38 moles
From the chemical equation we see that 1 moles of Zn produces 1 mole of ZnCl₂, so 0.38 moles of Zn will produce 0.38 moles of ZnCl₂.
molarity = number of moles / volume (L)
molarity of the ZnCl₂ solution = 0.38 / 0.285 = 1.33 M
Learn more about:
molarity
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