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Mashutka [201]
3 years ago
5

Which of the following acid-naming rules is INCORRECT 

Chemistry
2 answers:
oksano4ka [1.4K]3 years ago
7 0

<u>Answer:</u> The incorrect statement is all acid names end with -ic.

<u>Explanation:</u>

Acids are defined as the chemical species which donate hydrogen ions when dissolved in water.

HA(aq.)\rightarrow H^+(aq.)+A^-(aq.)

The nomenclature of the acids that are derived from the anions attached to hydrogen ion:

  • If the name of the anion attached ends with -ate, then the prefix of the acid is -ic. <u>For Example:</u> H_3PO_4, the anion is phosphate and the name of the acid is phosphoric acid.
  • If the name of the anion attached ends with -ite, then the prefix of the acid is -ous. <u>For Example:</u> H_2SO_3, the anion is sulfite and the name of the acid is sulfurous acid.
  • If the name of the anion attached ends with -ide, then the prefix of the acid is -ic. <u>For Example:</u> HCl, the anion is chloride and the name of the acid is hydrochloric acid.

Hence, the incorrect statement is all acid names end with -ic.

ad-work [718]3 years ago
6 0
<span>The answer to this question would be: A. all acid names end with "-ic"

Not all acid have "-id" suffix for their name. The example of this was already mentioned in the question as the sulfite ion will be called sulfurous acid. The "-ous" name is given to acid with lower oxidation state. Sulfuric acid will be the H2SO4 which have higher oxidation state.</span>
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First, we write the balanced equation for this reaction:

2KI + Pb(NO₃)₂ → 2KNO₃ + PbI₂

From this equation, we see that there are 2 moles of potassium iodide required for each mole of lead (II) nitrate. Moreover, we may use the formula:

Moles = volume (in L) * molarity

We find the molar relation ship for KI : Pb(NO₃)₂ to be 2 : 1. So:

M₁V₁ = 2M₂V₂

V₁ = 2M₂V₂/M₁
V₁ = 2 * 0.112 * 0.155 / 0.2
V₁ = 0.1736 L


The volume required is 173.6 mL
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Explanation:

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3 years ago
what is the mass of water vapor produced when 3.2 liters reacts with 8.7 liters of oxygen gas at STP?
uranmaximum [27]

Answer:

2.57g

Explanation:

First, let us write a balanced equation for the reaction. This is illustrated below:

2H2 + O2 —> 2H2O

Next let us determine the limiting reactant. This is achieved as follows:

From the equation,

2L H2 required 1L of O2.

Therefore, 3.2L of H will require = 3.2/2 = 1.6L of O2

From the calculation above, O2 is excess because the volume of O2 given from the question is far greater than the volume of O2 obtained from our calculation. Therefore, H2 is the limiting reactant.

Now let us covert 3.2L of H2 to mole. This is illustrated below:

1mole of a gas occupy 22.4L at stp

Therefore, Xmol of H2 will occupy 3.2L i.e

Xmol of H2 = 3.2/22.4 = 0.143mol

From the equation,

2moles of H2 produced 2moles of H2O.

Therefore, 0.143mol of H2 will also produce 0.143moles of H2O.

Now, we can obtain the mass of the water vapour produced by convert 0.143mol of H2O to gram. This is illustrated below:

Molar Mass of H2O = (2x1) + 16 = 2 + 16 = 18g/mol

Number of mole of H2O = 0.143mol

Mass of H2O =?

Mass = mole x Molar Mass

Mass of H2O = 0.143 x 18 = 2.57g

The mass of water vapour produce is 2.57g

8 0
3 years ago
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