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tekilochka [14]
3 years ago
12

Describe how hydrogen and oxygen form water.

Chemistry
2 answers:
bekas [8.4K]3 years ago
7 0
Hydrogen and Oxygen by themselves have 1 and 6 valence electrons, respectively. 8 valence electrons is stable, so the atoms form bonds with each other to achieve 8 valence e-.

1 H atom + 1 H atom + 1 O atom = 8 valence e-
sveta [45]3 years ago
3 0
The oxygen atom requires 2 electrons to complete its valance shell. Hydrogen is special in that it can eighter give or take one electron and still be stable. So hydrogen gives its electron  to oxygen, and two hydrogens fill up all of oxygen's  valance shell, and it forms water.
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When a reaction takes place in a SEALED FLASK,<br> the TOTAL MASS of the system...
Doss [256]
It should remain constant because of the law of conservation of mass and because the flask is sealed no mass will escape
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3 years ago
What mass of H2O is produced by the combustion of 1.00 mol of CH4?
kkurt [141]
CH4 : H2O
1 : 2

number of moles of H2O = 1.00 x 2
number of moles of H2O = 2.00mol

mass = number of moles x molar mass

mass of H2O = 2.00 x (1 + 1 + 16)
mass of H2O = 36g
8 0
2 years ago
Which type of hybridization is observed when central atom is located at the centre of regular tetrahedron
Ann [662]

Answer:

sp3 hybridization

Explanation:

Hybridization means the mixing of atomic orbitals to yield hybrid orbitals with characteristics that are different from that of the isolated atomic orbitals before the combination.

sp3 hybridization occurs when one s orbital is mixed with three p orbitals to yield four sp3 hybrid orbitals which can be used to bond to a central atom.

The central atom is then located at the center of a regular tetrahedron at a bond angle of 109°.

3 0
2 years ago
The reaction in which methane is burned, CH4 +202 --&gt; 2H20 + CO2, is an example of a
alexira [117]

Answer: Combustion

Explanation:

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8 0
3 years ago
Calculate the maximum volume (in mL) of 0.143 M HCl that each of the following antacid formulations would be expected to neutral
Nuetrik [128]

Answer:

a. The maximum volume of 0.143 M HCl required is 154.4 mL.

b. The maximum volume of 0.143 M HCl required is 135.7 mL.

Explanation:

a.

Al(OH)_3+3HCl\rightarrow AlCl_3+3H_2O

Mass of aluminum hydroxide = 350 mg =  0.350 g ( 1mg = 0.001 g)

Moles of aluminum hydroxide = \frac{0.350 g}{78 g/mol}=0.004487 mol

According to reaction ,3 moles of HCl neutralize 1 mole of aluminum hydroxide.Then 0.004487 mole of aluminum hydroxide will be neutralize by :

\frac{3}{1}\times 0.004487 mol=0.01346 mol of HCl.

Mg(OH)_2+2HCl\rightarrow MgCL_2+2H_2O

Mass of magnesium hydroxide = 250 mg =  0.250 g ( 1mg = 0.001 g)

Moles of magnesium hydroxide = \frac{0.250 g}{58 g/mol}=0.004310 mol

According to reaction ,2 moles of HCl neutralize 1 mole of magnesium hydroxide.Then 0.004310  mole of magnesium hydroxide will be neutralize by :

\frac{2}{1}\times 0.004310 mol=0.008621 mol of HCl.

Total moles of HCl required to neutralize both :

0.01346 mol + 0.008621 mol = 0.02208 mol

Molarity of the HCL solution = 0.143 M

Volume of the solution = V

Molarity=\frac{\text{Total moles of HCl}{\text{Volume in Liter}}

V=\frac{0.02208 mol}{0.143 M}=0.1544 L

1 L = 1000 mL

0.1544 L = 154.4 mL

The maximum volume of 0.143 M HCl required is 154.4 mL.

b.

CaCO_3+2HCl\rightarrow CaCl_2+H_2O+CO_2

Mass of calcium carbonate = 970mg =  0.970 g ( 1mg = 0.001 g)

Moles of calcium carbonate = \frac{0.970 g}{100 g/mol}=0.00970 mol

According to reaction ,2 moles of HCl neutralize 1 mole of calcium carbonate.Then 0.00970 mole of calcium carbonate will be neutralize by :

\frac{2}{1}\times 0.00970 mol=0.0194 mol of HCl.

Total moles of HCl required to neutralize calcium carbonate : 0.0194 mol

Molarity of the HCL solution = 0.143 M

Volume of the solution = V

Molarity=\frac{\text{Total moles of HCl}}{\text{Volume in Liter}}

V=\frac{0.0194 mol}{0.143 M}=0.1357 L

1 L = 1000 mL

0.1357 L = 135.7 mL

The maximum volume of 0.143 M HCl required is 135.7 mL.

4 0
3 years ago
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