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lubasha [3.4K]
3 years ago
5

For a particular redox reaction SO_3^2-– is oxidized to SO_4^2- and Cu^+2 is reduced to Cu . Complete and balance the equation f

or this reaction in basic solution. Phases are optional.
Chemistry
1 answer:
salantis [7]3 years ago
6 0

Answer:

SO₃²⁻ + Cu²⁺ + 2OH⁻ ⟶ Cu + SO₄²⁻ + H₂O

Explanation:

I find that the easiest way to balance an equation in basic solution is first to balance as if it were in acid and then convert to base.

Your skeleton equation is

SO₃²⁻ + Cu²⁺ ⟶ SO₄²⁻ + Cu

1. Separate the reaction into two half-reactions

SO₃²⁻ ⟶ SO₄²⁻

Cu²⁺ ⟶ Cu

2. Balance all atoms other than O and H

Done

3. Balance O

SO₃²⁻ + H₂O ⟶ SO₄²⁻

Cu²⁺ ⟶ Cu

4. Balance H

SO₃²⁻ + H₂O ⟶ SO₄²⁻ + 2H⁺

Cu²⁺ ⟶ Cu

5. Balance charge

SO₃²⁻ + H₂O ⟶ SO₄²⁻ + 2H⁺ + 2e⁻

Cu²⁺ + 2e⁻ ⟶ Cu

6. Equalize electrons transferred

1 × [ SO₃²⁻ + H₂O ⟶ SO₄²⁻ + 2H⁺ + 2e⁻]

1 × [ Cu²⁺ + 2e⁻ ⟶ Cu]

7. Add the two half-reactions

SO₃²⁻ + H₂O ⟶ SO₄²⁻ + 2H⁺ + 2e⁻]

<u>Cu²⁺ + 2e⁻ ⟶ Cu                                       </u>

SO₃²⁻ + Cu²⁺ + H₂O ⟶ Cu + SO₄²⁻ + 2H⁺

8. Convert to base

SO₃²⁻ + Cu²⁺ + H₂O ⟶ Cu + SO₄²⁻ + 2H⁺

<u>             2H⁺ + 2OH⁻ ⟶ 2H₂O                      </u>

SO₃²⁻ + Cu²⁺ + 2OH⁻ ⟶ Cu + SO₄²⁻ + H₂O

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For the reaction 2Fe + O2 = 2FeO, how many grams of iron oxide are produced from 8.00 mol of iron? when o2 is an excess
Yanka [14]

Answer:

The answer to your question is 576 grams of FeO

Explanation:

Balanced chemical reaction

                      2Fe  +  O₂  ⇒  2 FeO

       Reactant             Elements         Products

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Process

1.- Convert moles of Fe to grams

Atomic mass = 56 g

                         56 g of Fe ------------------ 1 mol

                           x               ------------------ 8 moles

                           x = (8 x 56) / 1

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2.- Use the coefficients of the balanced reaction to find the grams of FeO.

Molecular mass of FeO = 2[ 56 + 16]

                                       = 144 g

               2(56) g of Fe ----------------------- 144 g of FeO

               448 g             -----------------------  x

                x = (448 x 144) / 2(56)

                x = 64512 / 112

               x = 576 grams of FeO

                       

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