You just have to isolate x, so just divide by WQ on both sides to get:
Each part of the body of an animal is made up of cells.
Answer:
13.5
Explanation:
Molar mass of Fe2O3 = 2*56 + 16*3 = 112 + 48 =160 approximate value
Number of moles of Fe2O3 = mass/molar mass = 40/160 = 0.25 mol
The reaction is balanced. Fine
1 mol of Fe2O3--------> 2 mol of Al
0.25 mol--------> 0.25*2 = 0.5 mol of Al
Mass of Al required = Number of moles * Molar mass
= 0.5 * 27 = 13.5 g
Answer:
solubility of X in water at 17.0 
is 0.11 g/mL.
Explanation:
Yes, the solubility of X in water at 17.0 can be calculated using the information given.
Let's assume solubility of X in water at 17.0 is y g/mL
The geochemist ultimately got 3.96 g of crystals of X after evaporating the diluted solution made by diluting the 36.0 mL of stock solution.
So, solubility of X in 1 mL of water = y g
Hence, solubility of X in 36.0 mL of water = 36y g
So, 36y = 3.96
or, y = 
= 0.11
Hence solubility of X in water at 17.0 is 0.11 g/mL.
The no. of moles of the gas sample are present at the end is 0.486 moles
The ideal gas law is :
PV = nRT
here,
P is pressure = 4.00 atm
T is temperature = 21.7 °C = 294.7 K
n is moles = 1.90 moles
R is gas constant
V = n RT / P
= (1.90 × 0.082 × 294.7) / 4
= 11.47 L
Now when temperature is 302.1 K , pressure is 1.05 atm and volume is 11.47 L then the moles will be :
PV = n RT
n = PV / RT
= ( 1.05 × 11.47 ) /( 0.082 × 302.1 )
= 12.04 / 24.77
= 0.486 moles
Thus , A glass container was initially charged with 1.90 moles of a gas sample at 4.00 atm and 21.7 °C. some of the gas was released as the temperature was increased to 29.1 °C, so the final pressure in the container was reduced to 1.05 atm . the no. of moles of the gas sample are present at the end is 0.486 moles
To learn more about ideal gas law here
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