Nutrients and oxygen to all cells in the body.
Answer:
From my side the correct option is "A"
Explanation: Reasons for its correction are ,
1) Highly reactive: Nanoparticles are therefore extremely unstable and easily change themselves or react with active substances to reach a relatively stable state in some cases. This causes desired changes or undesired changes to nanoparticles and thus makes them exhibit a high reactivity and a poor stability.
2)Small size: Nanotechnology can provide rapid and sensitive detection of cancer-related molecules, enabling scientists to detect molecular changes even when they occur only in a small percentage of cells. Nanotechnology also has the potential to generate entirely novel and highly effective therapeutic agents.
The products of a combustion reaction is always CO2 + H20, then you would balance it out with the whole equation.
In this case it would be:
C3H8 + O2 -> CO2 + H2O
Balanced:
C3H8 + 5O2 -> 3CO2 + 4H2O
Answer:
Percentage composition of oxygen = 29.69%
Percentage composition of fluorine = 70.37
Explanation:
Given:
Mass of compound = 0.432 grams
Mass of oxygen = 0.128 grams
Find:
Percentage composition of oxygen
Percentage composition of fluorine
Computation:
Percentage composition of oxygen = [0.128/0.432]100
Percentage composition of oxygen = 29.69%
Percentage composition of fluorine = [(0.432 - 0.128)/0.432]100
Percentage composition of fluorine = 70.37
Mass of SiC = 2 g
<h3>Further explanation</h3>
Given
Reaction
SiO₂(s) + 3C(s) → SiC(s) + 2CO(g)
3.00 g of SiO₂
4.50 g of C
Required
mass of SiC
Solution
mol SiO₂ (MW=60,08 g/mol) :
= 3 g : 60.08 g/mol
= 0.0499
mol C(Ar = 12 g/mol) :
= 4.5 g : 12 g/mol
= 0.375
mol : coefficient of reactants =
SiO₂ : 0.0499/1 = 0.0499
C : 0.375/3 = 0.125
SiO₂ as a limiting reactant(smaller ratio)
Mol SiC based on mol SiO₂ = 0.0499
Mass SiC :
= mol x MW
= 0.0499 x 40,11 g/mol
= 2 g