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2 years ago

Dad gives the child on the sled a long push to set him in motion along the level surface

Physics

1 answer:

Alex_Xolod [135]2 years ago

5 0

Then he fell in a sewer with lots of poop and you try to escape but a river of pee came rushing down and wash you away

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A retail gasoline pump is able to fill a 14.0 gallon automobile tank in 1.50 minutes. What is the mass flow rate deliverd by the

Ludmilka [50]

We have volume of gasoline = 14.0 gallon

Time taken to fill automobile tank = 1.50 minutes

So volume rate = 14.0 gallon/1.50 minutes = 9.33 gallon/ minute

We have density of gasoline = 0.77 kg/L = 6.073 lb/US gal

Mass rate = Density * Volume rate

= 9.33 gallon/ minute*6.073 lb/US gal = 56.68 lb/min

So mass flow rate delivered by the gasoline pump in lbm/min = 56.68

6 0

3 years ago

Read 2 more answers

The net effect of each cycle of the sodium-potassium pump is to ____.? ?decrease the number of positively charged ions within th

stealth61 [152]

The correct answer may be A

3 0

2 years ago

Physics, calculating net force. Please work it out for me

Margarita [4]

Answer:

F = 2985.125 N

Explanation:

Given that,

The radius of curvature of the roller coaster, r = 8 m

Speed of Micheal, v = 17 m/s

Mass of body, m = 65 kg We need to find the net force acting on Micheal. Net force act the bottom of the circle is given by :

$F=\dfrac{mv^2}{r}+mg\\\\F=m(\dfrac{v^2}{r}+g)\\\\=65(\dfrac{17^2}{8}+9.8)\\\\=2985.125\ N$

So, the net force is 2985.125 N.

3 0

2 years ago

2. A brick is sitting on a building 22 m high. It has a mass of 7.9 kg. What amount of potential

Citrus2011 [14]

Answer:

1703.24J

Explanation:

Given parameters:

Mass of brick = 7.9kg

Height of building = 22m

Unknown:

Potential energy of the brick = ?

Solution:

The potential energy of a body is the energy at rest of the body. Mathematically;

P.E = mgh

m is the mass of the brick

g is the acceleration due to gravity

h is the height of the building

Insert the given parameters and solve;

P.E = 7.9 x 9.8 x 22 = 1703.24J

6 0

3 years ago

The gravitational force of attraction between two students sitting at their desks in physics class is 2.59 × 10−8 N. If one stud

motikmotik

<h2>The distance between students is 2.46 m</h2>

Explanation:

The force of attraction due to Newton's gravitation law is

F = $\frac{Gm_1m_2}{r^2}$

Here G is the gravitational constant

m₁ is the mass of one student

m₂ is the mass of second student .

and r is the distance between them

Thus r = $\sqrt{\frac{Gm_1m_2}{F} }$

If we substitute the values in the above equation

r = $\sqrt{\frac{6.673x10^-^1^1x31.9x30.0}{2.59x10^-^8} }$

= 2.46 m

3 0

3 years ago

Read 2 more answers