How does oceanic crust move along mid-ocean ridges?
2 answers:
You might be interested in
centripetal acceleration is given by formula
given that
now we have
so the ratationa frequency is given by
To solve this problem we will apply the linear motion kinematic equations. From the definition of the final velocity, as the sum between the initial velocity and the product between the acceleration (gravity) by time, we will find the final velocity. From the second law of kinematics, we will find the vertical position traveled.
Here,
v = Final velocity
= Initial velocity
g = Acceleration due to gravity
t = Time
At t = 4s, v = -30m/s (Downward)
Therefore the initial velocity will be
Now the position can be calculated as,
When it has the ground, y=0 and the time is t=4s,
Therefore the cliff was initially to 41.6m from the ground
Answer:
0.1040512455 N
0.05925 N
Explanation:
I = Current
B = Magnetic field
Separation between end points is
Effective force is given by
The force is 0.1040512455 N
The angle the force makes is given by
The direction is
The force is 0.05925 N
The direction is