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natta225 [31]
2 years ago
13

A boy exerts an unknown horizontal force as he pulls a 52 N sled across packed snow. The coefficient of friction is 0.12. If a p

erson weighing 650 N sits on the sled, what force is needed to pull the sled across the snow at constant speed?
Physics
2 answers:
Tems11 [23]2 years ago
7 0

Answer:

is there a pic?

Explanation:

7nadin3 [17]2 years ago
5 0

Answer:

0.62

Explanation:

Ff = mg = 52 N

Since the speed is constant, the friction

force equals the force exerted by the

girl, 36 N.

Ff = ukFn

so uK = Ff/Fn

= 36 N/52 N

= 0.69

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Answer:

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The L-ft ladder has a uniform weight of W lb and rests against the smooth wall at B. θ = 60. If the coefficient of static fricti
Colt1911 [192]

This question is incomplete, the complete question;

The L-ft ladder has a uniform weight of W lb and rests against the smooth wall at B. θ = 60. If the coefficient of static friction at A is μ = 0.4.

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Answer:

- the magnitude of force at point A is 79.1033 lb

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Explanation:

Given that;

∑'MA = 0

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therefore from equation 1

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we substitute in our values

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Net force at A will be

FA' = √( NA² + FA²)

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FA' = √( (76)² + (21.9393)²)

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FA' = 79.1033 lb

Therefore the magnitude of force at point A is 79.1033 lb

Now maximum possible frictional force at A

FA_max = μ × NA

so, FA_max = 0.4 × 76

FA_max = 30.4 lb

So by comparing, we can easily see that the actual friction force required for keeping the the ladder stationary i.e (FA) is less than the maximum possible friction available at point A.

Therefore since FA < FA_max; Ladder WILL NOT slip

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2 years ago
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