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leva [86]
3 years ago
5

Liquids and gases are highly compressible. a)True b)False

Physics
1 answer:
densk [106]3 years ago
5 0
True. 
Gas -> Liquid
At the GAS stage, the particles are wildly spread.
Liquid -> Solid
At a LIQUID stage, the particles are slightly more compressed.
and yeah you get the idea. 
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Define Work.<br>Thank You!​
Anna35 [415]

Answer:

<h2>work:</h2>

Activity in which one exerts strength or faculties to do or perform something. A job is an activity that a person engages in regularly to earn a livelihood.

<u>you are welcome!</u>

6 0
3 years ago
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Determine the two coefficients of static friction at B and at C so that when the magnitude of the applied force is increased to
stiks02 [169]

Now, there is some information missing to this problem, since generally you will be given a figure to analyze like the one on the attached picture. The whole problem should look something like this:

"Beam AB has a negligible mass and thickness, and supports the 200kg uniform block. It is pinned at A and rests on the top of a post, having a mass of 20 kg and negligible thickness. Determine the two coefficients of static friction at B and at C so that when the magnitude of the applied force is increased to 360 N , the post slips at both B and C simultaneously."

Answer:

\mu_{sB}=0.126

\mu_{sC}=0.168

Explanation:

In order to solve this problem we will need to draw a free body diagram of each of the components of the system (see attached pictures) and analyze each of them. Let's take the free body diagram of the beam, so when analyzing it we get:

Sum of torques:

\sum \tau_{A}=0

N(3m)-W(1.5m)=0

When solving for N we get:

N=\frac{W(1.5m)}{3m}

N=\frac{(1962N)(1.5m)}{3m}

N=981N

Now we can analyze the column. In this case we need to take into account that there will be no P-ycomponent affecting the beam since it's a slider and we'll assume there is no friction between the slider and the column. So when analyzing the column we get the following:

First, the forces in y.

\sum F_{y}=0

-F_{By}+N_{c}=0

F_{By}=N_{c}

Next, the forces in x.

\sum F_{x}=0

-f_{sB}-f_{sC}+P_{x}=0

We can find the x-component of force P like this:

P_{x}=360N(\frac{4}{5})=288N

and finally the torques about C.

\sum \tau_{C}=0

f_{sB}(1.75m)-P_{x}(0.75m)=0

f_{sB}=\frac{288N(0.75m)}{1.75m}

f_{sB}=123.43N

With the static friction force in point B we can find the coefficient of static friction in B:

\mu_{sB}=\frac{f_{sB}}{N}

\mu_{sB}=\frac{123.43N}{981N}

\mu_{sB}=0.126

And now we can find the friction force in C.

f_{sC}=P_{x}-f_{xB}

f_{sC}=288N-123.43N=164.57N

f_{sC}=N_{c}\mu_{sC}

and now we can use this to find static friction coefficient in point C.

\mu_{sC}=\frac{f_{sC}}{N}

\mu_{sC}=\frac{164.57N}{981N}

\mu_{sB}=0.168

3 0
3 years ago
List three devices that use electric current from batteries and three that use regular house current.
Bond [772]
Charger
counsels
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Fan
light
car
4 0
4 years ago
A 5 kg fish swimming at 1 m/s swallows an absentminded 500 g fish swimming toward it at a veloc- ity that brings both fish to a
morpeh [17]

Answer:

v = 10 m/s

Explanation:

given,

Mass of large fish, M = 5 Kg

speed of swimming, v' = 1 m/s

mass of small fish, m = 500 g = 0.5 Kg

speed of the fish = v

using conservation of momentum

m v + M v' = M u' + m u

final speed of both the speed is zero.

- 0.5 x v + 5 x 1  = 0

negative sign is used because small fish is moving in opposite direction.

now,

0.5 v = 5

v = 10 m/s

hence, the speed of the small fish is equal to 10 m/s.

8 0
3 years ago
Which of the following is considered to be a fine motor skill?
Bas_tet [7]

Answer:

drawing because Fine motor skills are the ability to make movements using the small muscles in our hands and wrists.

5 0
3 years ago
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