Answer:
K = 227.04 W/m.°C
Explanation:
First we need to find the heat required to melt the ice:
q = m H
where,
q = heat required = ?
m = mass of the ice = 8.5 g = 8.5 x 10⁻³ kg
H = Latent heat of fusion of ice = 3.34 x 10⁵ J/kg
Therefore,
q = (8.5 x 10⁻³ kg)(3.34 x 10⁵ J/kg)
q = 2839 J
Now, we find the heat transfer rate through rod:
Q = q/t
where,
t = time = (10 min)(60 s/1 min) = 600 s
Q = Heat Transfer Rate = ?
Therefore,
Q = 2839 J/600 s
Q = 4.73 W
From Fourier's Law of Heat Conduction:
Q = KA ΔT/L
where,
K = Thermal Conductivity = ?
A = cross sectional area = 1.25 cm² = 1.25 x 10⁻⁴ m²
L = Length of rod = 60 cm = 0.6 m
ΔT = Difference in temperature = 100°C - 0°C = 100°C
Therefore,
4.73 W = K(1.25 X 10⁻⁴ m²)(100°C)/0.6 m
K = (4.73 W)/(0.0208 m.°C)
<u>K = 227.04 W/m.°C</u>
A battery is a device that stores chemical energy and converts it to electrical energy. Two terminals made of different chemicals (typically metals), the anode and the cathode; and the electrolyte, which separates these terminals.
Hope I get it and hope this helps
Answer:
Explanation:
initial velocity, u = 0 m/s
time, t = 8.99 s
final velocity, v = 21.9 m/s
diameter of tyre, D = 57.5 cm
(a) Let a is the acceleration, and n be the number f revolutions made by the tyre.
Use first equation of motion
v = u + at
21.9 = 0 + a x 8.99
a = 2.44 m/s²
Use third equation of motion
v² = u² + 2 a s
21.9 x 21.9 = 0 + 2 x 2.44 x s
s = 98.28 m
Circumference of wheel, S = π x D = 3.14 x 0.575 = 1.8055 m
number of revolutions, n = distance / circumference
n = 98.28 / 1.8055
n = 54.4
With air resistance, acceleration decreases. Without air resistance, acceleration remains the same throughout the fall ... the acceleration of gravity.
Have you ever heard this phrase, "What weighs more, a ton of feathers, or a ton of lead?" The answer is, they weigh the same, however the ton of feathers takes up more space than the ton of lead. So to answer your question, the answer is yes, and no. Depending on what the substance is will determine your answer. I hope that i helped.
