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kifflom [539]
3 years ago
6

Consider the table below. Which of the following data sets depict an accelerating object? Mark all that apply.

Physics
1 answer:
Gre4nikov [31]3 years ago
7 0

Answer:

A and B

Explanation:

The data sets that depict an accelerating object is Data Set A & Data Set B.

The both data sets show that the body is accelerating. Also, they show that the body started from rest (0m/s) at a 0sec.

Data Set A shows a non-constant acceleration which has changing amount of velocity with change in time. While Data Set B shows a constant acceleration which has constant amount of velocity with change in time.

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Kyle, a 95.0 kg football player, leaps straight up into the air (with no horizontal velocity) to catch a pass. He catches the 0.
babymother [125]

Answer:

The initial speed of the ball was 26.2 m/s

Explanation:

When the football player is in the air at his maximum height the vertical component of velocity is zero, To obtain the horizontal velocity when the player catches the ball we need to apply the linear momentum conservation theorem:

m_1*v_{o1}+m_2*v_{o2}=m_t*v_f\\0.430kg*(v)+m_2*(0)=mt*vt

we need to obtain the time taken to go down.

y=Y_o+v_o*t-\frac{1}{2}g*t^2\\\\0=0.589-4.9t^2\\solving:\\t_1=0.346s\\

We have a horizontal displacement and the time taken to stop, so:

v_f=\frac{d}{t}=\frac{0.0409m}{0.346s}=0.118m/s

so:

0.430kg*(v)+m_2*(0)=(m1+m2)*vt\\v=\frac{(95.0kg+0.430kg)*0.118m/s}{0.430kg}\\\\v=26.2m/s

8 0
3 years ago
Agility refers to a person's level of flexibility.
tekilochka [14]
False, agility is more about how fast you are
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What potential difference is needed to give a helium nucleus (q=2e) 85.0 kev of kinetic energy?
Vilka [71]
The kinetic energy K given to the helium nucleus is equal to its potential energy, which is 
E=q \Delta V
where q=2e is the charge of the helium nucleus, and \Delta V is the potential difference applied to it.
Since we know the kinetic energy, we have
E=K=85~keV=q \Delta V
and from this we can find the potential difference:
\Delta V =  \frac{K}{q}= \frac{85~keV}{2e}=42.5~kV

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Define 1 kg of mass as international standard​
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8 0
3 years ago
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A manufacturer selected a metal to use in producing a lightweight button for clothing. A metal that has a density of 2.71 g/cm3
Natali5045456 [20]

Just find the density of every metal and select the one with a density of 2.71 g/cm³ . This is:

Metal 1

ρ = m/V

ρ = 22.1 g / 3 cm³

ρ = 7.367 g / cm³

Metal 2

ρ = m/V

ρ = 42 g / 4 cm³

ρ = 10.5 g / cm³

Metal 3

ρ = m/V

ρ = 9.32 g / 5 cm³

ρ = 1.864 g / cm³

Metal 4

ρ = m/V

ρ = 8.13 g / 3 cm³

ρ = 2.71 g / cm³

<h2>R / Metal 4 was selected.</h2>
4 0
3 years ago
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