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lesantik [10]
3 years ago
6

Which units are used to measure both velocity and speed?

Physics
2 answers:
Stells [14]3 years ago
5 0

                 (Any unit of distance)
divided by
                 (any unit of time)

becomes a unit of speed.  Some favorites are  mile/hour,
meter/second, and  foot/second.

Speed is a part of velocity, so the same units are involved
in velocity.  But velocity needs more than that.

When you have the distance and the time, you know the
speed completely ... there's no more to know about it.

But speed is only part of velocity.  In addition to speed,
there's more to know in order to have a velocity.  That's
the direction of the speed. 
irina1246 [14]3 years ago
4 0
The SI unit for velocity and speed is meters per second
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Y_Kistochka [10]

Answer:

By looking at the graph it looks like its decreasing but you may want to re- read  the question to make sure that I am correct.I hope that this helps!

Explanation:

6 0
3 years ago
Ira is concerned about his posture. He tests it by seeing how long he can hold good posture and finds that he feels the most dis
larisa [96]

Answer: C

Explanation:

JUST TO SIMPLE

6 0
3 years ago
(b) During one day, 250 kg of water is pumped through
ser-zykov [4K]

Answer: The energy incident on the solar panel during that day is 9.24 \times 10^{7} J.

Explanation:

Given: Mass = 250 kg

Initial temperature = 16^{o}C

Final temperature = 38^{o}C

Specific heat capacity = 4200 J/kg^{o}C

Formula used to calculate the energy is as follows.

q = m \times C \times (T_{2} - T_{1})

where,

q = heat energy

m = mass of substance

C = specific heat capacity

T_{1} = initial temperature

T_{2} = final temperature

Substitute the values into above formula as follows.

q = 250 kg \times 4200 J/kg^{o}C \times (38 - 16)^{o}C\\= 250 kg \times 4200 J/kg^{o}C \times 22^{o}C

As it is given that water absorbs 25% of the energy incident on the solar panel. Hence, energy incident on the solar panel can be calculated as follows.

\frac{25}{100} \times q = 250 kg \times 4200 J/kg^{o}C \times 22^{o}C\\q = 9.24 \times 10^{7} J

Thus, we can conclude that the energy incident on the solar panel during that day is 9.24 \times 10^{7} J.

4 0
3 years ago
When the hydrogen atom makes the transition from the n=2 to the n=1 energy level, it emits a photon. This photon can be absorbed
bazaltina [42]

Answer:

n_{fn}= 4

Explanation:

To solve this exercise we will use Bohr's atomic model

               E_{n} = - 13.606 / n²     [eV]

The transition from level n = 2 to level n = 1 is valid

               E_{21} = - 13.606 [¼ -1/1]

               E_{21} = 10.2045 eV

Bohr's model for atoms with only one electron is

               E_{n} = -13.606 Z² / n²

Where Z is the atomic number of the atom.

In this case the helium atom has an atomic number of Z = 2 from the level n₀ = 2 let's look up to what level it reaches

         ΔE = -13.606 [4 /  n_{fn}² - 4/4]

         4 / n_{fn}² = -ΔE / 13.606 + 1

         4 / n_{fn}² = -10.2045 / 13.606 +1 = -0.75 +1

         4 / n_{fn}² = 0.25

        n_{fn} = √ 4 / 0.25

        n_{fn}= 4

8 0
3 years ago
A plane electromagnetic wave with wavelength 3.0 m, travels in free space in the+xdirection with its electric field vector~E, of
mart [117]

Answer:

    f =1 10⁸ Hz

Explanation:

The speed of an electromagnetic wave is given by

          c = Lam f

In our case, the wavelength is 3.0 m, so we can clear the frequency

         f = c / Lam

         f = 3 108/3.

         f =1 10⁸ Hz

6 0
3 years ago
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