Answer:
v = 79.2 m/s
Solution:
As per the question:
Mass of the object, m = 250 g = 0.250 kg
Angle,
Coefficient of kinetic friction,
Mass attached to the string, m = 0.200 kg
Distance, d = 30 cm = 0.03 m
Now,
The tension in the string is given by:
(1)
Also
T = m(g + a)
Thus eqn (1) can be written as:
Now, the speed is given by the third eqn of motion with initial velocity being zero:
where
u = initial velocity = 0
Thus
Red Skull's relative velocity to Captain America, towards the left front of the
truck is approximately <u>33.23 m/s</u> in a direction from the North of
approximately <u>9.18°</u>.
Reasons:
Assumptions;
Taking the north direction as positive.
The activity takes place on the trucks.
The trucks are moving towards each other.
Solution:
Vector form of net speed of Red Skull, is given as follows;
Vector form of the net speed of Captain America is given as follows;
Relative velocity, v₁₂ = v₁ - v₂
∴ v₁₂ = (-( × 3.5) - (
× 4.0))·i + ((
× 3.5 + 12.5) + (
× 4.0 + 15))·j
Red Skull's velocity relative to Captain America, v₁₂ = ·i +
·j
Therefore;
Therefore;
The magnitude of the velocity, |v₁₂|, is given as follows;
The magnitude of Red Skull's velocity relative to Captain America is,
therefore;
|v₁₂| ≈ <u>33.23 m/s</u>
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