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3 years ago

Wladimir Köppen’s climate system was developed _____.

Physics

1 answer:

son4ous [18]3 years ago

5 0

Answer:

From 1846 to 1940 it would be about 1950

Explanation:

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Two particles with charges +6e and -6e are initially very far apart (effectively an infinite distance apart). They are then fixe

JulijaS [17]

Answer:

$\rm EPE_{final}-EPE_{initial}=-1.478\times 10^{-15}\ J.$

Explanation:

Given charges are:

$\rm q_1 = +6e.\\q_2 = -6e.$

The electric potential energy of a charge due to the electric field of another charge is given by

$\rm EPE=\dfrac{kq_1q_2}{r}.$

where,

k = Coulomb's constant, having value = $\rm 9\times 10^9\ Nm^2/C^2.$
r = distance between the charges.

When the charges are infinite distance apart, $\rm r = \infty$ ,

$\rm EPE_{initial} = \dfrac{kq_1q_2}{r}=0\ J.$

When the charges are $\rm 5.61\times 10^{-12}\ m$ apart, $\rm r=5.61\times 10^{-12}\ m$ ,

$\rm EPE_{final}=\dfrac{kq_1q_2}{r}\\=\dfrac{(9\times 10^9)\times (+6e)\times (-6e)}{5.61\times 10^{-12}}\\=-5.775\ e^2\times 10^{22}.$

Here, e is the charge on one electron, such that, $\rm e = -1.6\times 10^{-19}\ C$ .

Therefore,

$\rm EPE_{final}=-5.775\times (-1.6\times 10^{-19})^2\times 10^{22} = -1.478\times 10^{-15}\ J.$

Thus,

$\rm EPE_{final}-EPE_{initial}=-1.478\times 10^{-15}-0=-1.478\times 10^{-15}\ J.$

4 0

3 years ago

Equation of uniformly accelerated motion

Kruka [31]

Answer:

x₂ = x₁ + v₁t + at²/2

Explanation:

Right out of the textbook.

6 0

3 years ago

A person absentmindedly walks off the edge of a tall cliff. They will fall 50 m into either

kifflom [539]

The man can survive, and he lands 12.1 m from the base of the cliff (into the lake)

Explanation:

The motion of the person is equivalent to the motion of a projectile, which consists of two separate motions:

- A uniform motion (constant velocity) along the horizontal direction

- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction

We start by analyzing the vertical motion, to find the time it take for the person to reach the ground level. We can use the following suvat equation:

$s=ut+\frac{1}{2}gt^2$

where

s = 50 m is the vertical distance covered (the height of the cliff)

u = 0 is the initial vertical velocity

$g=9.8 m/s^2$ is the acceleration of gravity

t is the time of flight

Solving for t,

$t=\sqrt{\frac{2s}{g}}=\sqrt{\frac{2(50)}{9.8}}=3.19 s$

The person moved horizontally at a constant speed of

$v_x = 3.8 m/s$

So, the horizontal distance covered by the man during his flight will be

$d_x = v_x t = (3.8)(3.19)=12.1 m$

So, the man will land on the lake (which starts from 12 m), so he can survive.

Learn more about projectile motion:

brainly.com/question/8751410

#LearnwithBrainly

8 0

3 years ago

How does potential difference behave in a parallel circuit

Illusion [34]

The same voltage will appear across all resistors in parallel.

6 0

3 years ago

Read 2 more answers

Calculate the watts of power expended when a force 400 N travels 12 meters over 10 seconds.

Pachacha [2.7K]

Answer:

Explanation:

Example

7 0

3 years ago