Tech A says that in some cases, the electronic brake control module can be programmed with a new tire size to restore proper ele
1 answer:
You might be interested in
Answer: 37.4K
Explanation:
See attachment
Answer:
Yes, fracture will occur
Explanation:
Half length of internal crack will be 4mm/2=2mm=0.002m
To find the dimensionless parameter, we use critical stress crack propagation equation
and making Y the subject
Where Y is the dimensionless parameter, a is half length of crack, K is plane strain fracture toughness, is critical stress required for initiating crack propagation. Substituting the figures given in question we obtain
When the maximum internal crack length is 6mm, half the length of internal crack is 6mm/2=3mm=0.003m
and making K the subject
and substituting 260 MPa for
while a is taken as 0.003m and Y is already known
Therefore, fracture toughness at critical stress when maximum internal crack is 6mm is 42.455 Mpa and since it’s greater than 40 Mpa, fracture occurs to the material
Answer:
A.) 0.3088
B.) 0.0017
C.) part A
Explanation:
A.)
B.)
C.) Since the seat performance for an individual pilot is more important than 39 different pilots.
Answer:
Explanation:
In this problem you need to define the force that acts upon a beam in a 3 point bending problem. I put a picture of the problem taken from Wikipedia:
In this problem the flexural strength is defined with the following formula:
where F is the force applied, L the length between the two rods, b the width of the ceramic block and d it's height.
The force is then defined as:
