Answer:
12.84 mg/L
Explanation:
We are given;
Volume of lake; V = 1.1 x 10^(6) m³
decay coefficient; K = 0.10/day = 0.1/(24 × 60 × 60) /s = 0.00000115741 /s
Factory rate: Q_f = 4.3 m³/s
Factory concentration: C_f = 100 mg/L
Stream rate: Q_s = 34 m³/s
Stream Concentration: C_s = 2.3 mg/L
Now, to find the steady state concentration of pollutant in the lake, we will use the formula;
(Q_s•C_s) + (Q_f•C_f) = (Q_f + Q_s)C_L + (KV•C_L)
Where C_L is the steady state concentration of pollutant in the lake.
Thus, making C_L the subject, we have;
C_L = [(Q_s•C_s) + (Q_f•C_f)]/(Q_f + Q_s + K•V)
Plugging in the relevant values gives;
C_L = ((34 × 2.3) + (4.3 × 100))/(4.3 + 34 + (0.00000115741 × 1.1 × 10^(6)))
C_L = 12.84 mg/L
youn need to use your hands
Answer:
a) 149 kJ/mol, b) 6.11*10^-11 m^2/s ,c) 2.76*10^-16 m^2/s
Explanation:
Diffusion is governed by Arrhenius equation

I will be using R in the equation instead of k_b as the problem asks for molar activation energy
I will be using

and
°C + 273 = K
here, adjust your precision as neccessary
Since we got 2 difusion coefficients at 2 temperatures alredy, we can simply turn these into 2 linear equations to solve for a) and b) simply by taking logarithm
So:

and

You might notice that these equations have the form of

You can solve this equation system easily using calculator, and you will eventually get

After you got those 2 parameters, the rest is easy, you can just plug them all including the given temperature of 1180°C into the Arrhenius equation

And you should get D = 2.76*10^-16 m^/s as an answer for c)
Answer:
a) 
b) 
Explanation:
From the question we are told that:
Cast-iron block Dimension:
Length
Width 
Feed
Depth 
Diameter 
Number of cutting teeth 
Rotation speed 
Generally the equation for Approach is mathematically given by



Therefore
Effective length is given as



a)
Generally the equation for Machine Time is mathematically given by

Where



Therefore


b)
Generally the equation for Material Removal Rate. is mathematically given by


