Answer:
The match
Explanation:
You can light both the lantern and the candle if you light the match first.
I don't know of this is a homework question, but I answered it anyway :)
Answer:
(b) Given the Weibull parameters of example 11-3, the factor by which the catalog rating must be increased if the reliability is to be increased from 0.9 to 0.99.
Equation 11-1: F*L^(1/3) = Constant
Weibull parameters of example 11-3: xo = 0.02 (theta-xo) = 4.439 b = 1.483
Explanation:
(a)The Catalog rating(C)
Bearing life:
Catalog rating: 
From given equation bearing life equation,

we Dividing eqn (2) with (1)

The Catalog rating increased by factor of 1.26
(b) Reliability Increase from 0.9 to 0.99

Now calculating life adjustment factor for both value of reliability from Weibull parametres


Similarly

Now calculating bearing life for each value

Now using given ball bearing life equation and dividing each other similar to previous problem

Catalog rating increased by factor of 0.61
Answer:
a. 5m
b. r = 0.16 e^-80.5◦
c. Zpn = (115.7 + j27.4) ohms
d. Vi = 2.2e^-j22.56◦ volts
e. Vi(t) = 2.2 cos (8π × 107t − 22.56◦ ) Volts
Explanation:
In this question, we are tasked with calculating a series of terms.
Please check attachment for complete solution and step by step explanation