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guapka [62]
3 years ago
6

Select the correct text in the passage.

Engineering
2 answers:
frutty [35]3 years ago
8 0

Answer:

The gauge converts the charge into a measurable electrical signal.

Explanation:

trust me

sineoko [7]3 years ago
5 0
It is habahi Yw with yuuuuuy I am a little more confused about
You might be interested in
6.28 A six-lane freeway (three lanes in each direction) in rolling terrain has 10-ft lanes and obstructions 4 ft from the right
dimulka [17.4K]

Answer:

Assume Base free flow speed (BFFS) = 70 mph

Lane width = 10 ft

Reduction in speed corresponding to lane width, fLW = 6.6 mph

Lateral Clearance = 4 ft

Reduction in speed corresponding to lateral clearance, fLC = 0.8 mph

Interchanges/Ramps = 9/ 6 miles = 1.5 /mile

Reduction in speed corresponding to Interchanges/ramps, fID = 5 mph

No. of lanes = 3

Reduction in speed corresponding to number of lanes, fN = 3 mph

Free Flow Speed (FFS) = BFFS – fLW – fLC – fN – fID = 70 – 6.6 – 0.8 – 3 – 5 = 54.6 mph

Peak Flow, V = 2000 veh/hr

Peak 15-min flow = 600 veh

Peak-hour factor = 2000/ (4*600) = 0.83

Trucks and Buses = 12 %

RVs = 6 %

Rolling Terrain

fHV = 1/ (1 + 0.12 (2.5-1) + 0.06 (2.0-1)) = 1/1.24 = 0.806

fP = 1.0

Peak Flow Rate, Vp = V / (PHV*n*fHV*fP) = 2000/ (0.83*3*0.806*1.0) = 996.54 ~ 997 veh/hr/ln

Vp < (3400 – 30 FFS)

S = FFS

S = 54.6 mph

Density = Vp/S = (997) / (54.6) = 18.26 veh/mi/ln

7 0
3 years ago
An ac source of period T and maximum voltage V is connected to a single unknown ideal element that is either a resistor, and ind
Misha Larkins [42]

Answer:

The unknown element is Capacitor.

Explanation:

The sinusoidal voltage is given as:

v(t) = V Sin (ωt + Ф)

Where:

V = Amplitude of Voltage

ω = 2π / T = > Time period (T)

Ф = phase shift

Considering no horizontal phase shift in the wave form, the equation can be written as:

v(t) = V Sin (ωt)--------(1)

Since, current in the capacitor can be given as:

i(t) = C dv(t)/dt = ωCV Cos (ωt)--------(2)

Now, checking all conditions:

At t=0 :

Equation (1) implies:

v(t) = V Sin [(2π/T)(0)] = V Sin (0)

v(t) = 0

The above finding satisfies the condition in the question. Now checking other conditions.

At t = T/4:

Equation (2) implies:

i(t) = ωCV Cos [(2π/T)(T/4)] = ωCV Cos [(π/2)] = ωCV (0)

i(t) = 0

At t = T/2 :

Equation (2) implies:

i(t) = ωCV Cos [(2π/T)(T/2)] = ωCV Cos [(π)] = ωCV (-1)

i(t) = - ωCV = max amplitude of current in negative direction

All three conditions of voltage and currents of question are satisfied with equations of capacitor hence, the unknown element is capacitor.

4 0
3 years ago
The author uses the example of the flameless candle to illustrate that​
krek1111 [17]

Answer:

I don't necessarily know the context of the text you are talking about, but a flameless candle could represent how there no more light in the author's life, which could represent a lack of happiness or a loss. Hope this helps!

Explanation:

4 0
2 years ago
Read 2 more answers
Several applications are listed below. Determine the relative importance of the resilience and toughness of the materials chosen
Norma-Jean [14]

Answer:

they are important together, but if you want to use just one future you must think about which one is first needed. and then try to learn for economical so don't use more money

5 0
3 years ago
A liquid stream containing solute A and carrier liquid C enters a packed column. The solute is to be stripped using pure gas B.
Gennadij [26K]

Answer:

the height of packing required for this separation is 15.85 m

Explanation:

Given that :

liquid stream (A+C) enters a packed column which the solute is stripped by using a pure gas B

The solute flowrate (L_s) = 150 kmole/hr

Mole fraction of the solute (x_2) = 7% = 0.07

(A+C)liquid = x_1 = 0.01

Pure gas (G_s) = 500 kmole/hr

y_1 = 0

The delivery force in the gas phase & liquid phase is expressed as:

(K_x)(x_2-x_1) = k_y(y_2-y_1)

Given that (K_x)_a = 75 kmole/hr m³ and equilibrium relationship y_A = 0.4x_A

Then :

K_{xa}(x_2-x_1) = (k_y)_a(y_2-y_1)

75(0.07-0.01)=(k_y)_a(y_2-0)

where ;

y_2 = 0.4x_2

= 0.4(0.07)

= 0.028

75(0.06)=(k_y)_a(0.028)

(k_y)_a = \frac{4.5}{0.028}

(ky)_a = 160.71 \ kmol/hr.m^3

NOW; the overall mass transfer coefficient on the liquid phase is :-

\frac{1}{(K_{ox})_a} = \frac{1}{(K_x)_a}+ \frac{1}{m(K_y)_a}

where m= slope = 0.4

\frac{1}{(K_{ox})_a} = \frac{1}{75}+ \frac{1}{0.4(160.71)}

{(K_{ox})_a} = 34.61 \  kmol/hr.m^3

Finally; the height of the tower (z) is = (HTU)_{oL}(NTU)_{oL}

(HTU)_{oL} = \frac{\frac{L_s}{s} }{(K_{ox})_a}

where :

s = 1m²

L_s = 150 kmol/hr

(HTU)_{oL} = \frac{\frac{150}{1} }{34.61} = 4.33 m

(NTU)_{oL} = e^x [\frac{(\frac{x_2-\frac{y_1}{m} }{x_1-\frac{y_1}{m} })(1-A)+A }{1-A} ]

where A  = \frac{L_s}{G_s *m} = \frac{150}{500(0.4)}

= 0.75

Then:

(NTU)_{oL} = e^x [\frac{(\frac{0.07-0 }{0.01-0 })(1-0.75)+0.75 }{1-0.75} ]

(NTU)_{oL} =3.66 \ m

the height of the tower (z) is = (HTU)_{oL}(NTU)_{oL}

= (4.33)(3.66)

=15.85 m

Thus, the height of packing required for this separation is 15.85 m

7 0
3 years ago
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