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Lady bird [3.3K]
4 years ago
13

Please help on this one?

Physics
1 answer:
Nonamiya [84]4 years ago
3 0

30 or c because 60-30=30

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One end of a string 6.26 m long is moved up and down with simple harmonic motion at a frequency of 95 Hz . The waves reach the o
uranmaximum [27]

Answer:

Explanation:

Given

length of string L=6.26\ m

frequency f=95\ Hz

time taken by wave to reach at other end t=0.5\ s

speed of  wave is given by

v=\frac{length\ of\ string}{time\ taken}

v=\frac{6.26}{0.5}

v=12.52\ m/s

wavelength of is given by

\lambda =\frac{velocity}{frequency}

\lambda =\frac{12.52}{95}

\lambda =0.131\ m                          

4 0
3 years ago
Bus starts from rest if the acceleration of the bus is 0.5 MS square what will be the velocity at the end of two minutes and wha
beks73 [17]

Answer:

1. 60 m/s.

2. 3600 m.

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 0

Acceleration (a) = 0.5 m/s²

Time (t) = 2 mins

Final Velocity (v) =?

Distance travelled (s) =?

1. Determination of the velocity at the end of 2 minutes.

Initial velocity (u) = 0

Acceleration (a) = 0.5 m/s²

Time (t) = 2 mins = 2 x 60 = 120 secs

Final Velocity (v) =?

v = u + at

v = 0 + (0.5 x 120)

v = 60 m/s

Therefore, the velocity at the end of 2 minutes is 60 m/s.

2. Determination of the distance travelled.

Initial velocity (u) = 0

Acceleration (a) = 0.5 m/s²

Final velocity (v) = 60 m/s

Distance travelled (s) =..?

v² = u² + 2as

60² = 0 + 2 x 0.5 x s

3600 = 1 x s

s = 3600 m

Therefore, the distance travelled is 3600 m.

6 0
3 years ago
Which of these can be impacted due to climate?
tester [92]
Is it a muti choose or normal i will answer it once for each
muti 1 A B
normal 2 A
3 0
4 years ago
Read 2 more answers
Jessica is visiting a park with her mother. Jessica sits on a swing. Her mother pulls the swing to a height of 3 meters above th
Tpy6a [65]

You are given Jessica's height of the swing 3 meters above the ground, velocity at 5m/s²  and her mass of 44 kilograms. Since there is no image given, I will assume that the position at maximum and minimum height, that is 3 and 0 meters.


Position at maximum height

PE = mgh

PE = 44 kg *9.8m/s²*3

PE = 1,294 J


Position at minimum height

PE = 0 J


Position at maximum velocity

KE = 1/2*mv²

KE = 1/2*44 kg*(5m/s²)²

KE = 550 J


Position at minimum velocity

KE = 0 J



8 0
3 years ago
All biomes don’t have the same level of biodiversity. What seems to be the optimal conditions for high biodiversity?
irinina [24]

Answer:

See the answer below

Explanation:

The optimal conditions for high biodiversity seem to be a <u>warm temperature</u> and <u>wet climates</u>.

<em>The tropical areas of the world have the highest biodiversity and are characterized by an average annual temperature of above 18 </em>^oC<em> and annual precipitation of 262 cm. The areas are referred to as the world's biodiversity hotspots. </em>

Consequently, it follows logically that the optimal conditions for high biodiversity would be a warm temperature of above 18 ^oC and wet environment with annual precipitation of not less than 262 cm.

The variation in temperature and precipitation across biomes can thus be said to be responsible for the variation in the level of biodiversity in them.

6 0
3 years ago
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