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olya-2409 [2.1K]
3 years ago
15

In order to simulate weightlessness for astronauts in training, they are flown in a vertical circle. if the passengers are to ex

perience weightlessness, how fast should an airplane be moving at the top of a vertical circle with a radius of 2.50 km
Physics
1 answer:
sleet_krkn [62]3 years ago
8 0
The answer is "156.6 m/s".

This is how we calculate this;

-N + mg = ma = mv²/r

For "weightlessness" N = 0, so

0 = mg - mv²/r 

g - v²/r = 0 

v =√( gr)
g = 9.8 and r = 2.5km = 2500 m

v = √(9.8 x 2500)

= 156.6 m/s
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A U-tube with a cross-sectional area of 1.00 cm2 is open to the atmosphere at both ends. Water is poured into the tube until the
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Answer:

0.89 g/cm^3 = 890 kg/m^3

Explanation:

Cross sectional area of U-tube ( A ) = 1.00 cm^2

volume of oil ( V )  = 5.00 cm^3

change between top surface = 0.550 cm

height of oil = 5 cm  ( volume / area )

height of water = 5 - 0.550 = 4.45 cm

pressure at the oil-water junction = Pressure on the second side of the U-tube at same level

Po * g * Hoil = Pw * g * Hwater

Po * 5 = 1 * 4.45

∴ Density of oil ( Po ) = 4.45 / 5  g/cm^3 = 0.89 g/cm^3

8 0
3 years ago
What are the products of the double-replacement reaction between potassium bromide and silver nitrate? Name the resulting compou
timofeeve [1]

Explanation:

A double replacement reaction is a reaction in which two different compounds are mixed together and both their cations and anions get exchanged with each other respectively.

When potassium bromide reacts with silver nitrate then it results in the formation of potassium nitrate and silver bromide.

The chemical reaction equation is as follows.

        KBr + AgNO_{3} \rightarrow KNO_{3} + AgBr

6 0
3 years ago
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When gases, liquids, or solids are in contact with a moving object, the flow of
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Place your hands on the side of your head, with your palms facing forward. This should look like you have given yourself large e
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3 years ago
CHAPTER 6: KINETICS OF A PARTICLE
vekshin1

Explanation:

Work done by winch = kinetic energy of car

∫ T ds = ½ mv²

∫ 225s ds = ½ mv²

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v = 3 m/s

8 0
3 years ago
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