Answer:
No. of moles, n = 25.022 moles
Given:
Volume of gas in tank, V = 29.1 l
Temperate of gas, T =
= 273 + 35.8 = 308.8 K
Pressure of gas, P = 21.8 atm
Solution:
Making use of the ideal gas equation which given as:
PV = nRT
where
R = Rydberg's constant = 0.0821 L-atm/mol-K
Re-arranging the above formula for 'n' and putting the values in the above formula:

n = 25.022
P₁V₁ / T₁ = P₂V₂ / T₂
1.6 × 168 /255 = 1.3 × V₂ / 285
V₂ = 1.6 × 168 × 285 / (1.3 × 255)
V₂ = 231.095
The final volume = 231 cm³
Answer:
Explanation:
Let the ball is thrown upwards with speed u and reaches upto height h.
Use III equation of motion

here, final velocity v = 0
So, 
Now as the ball reaches the maximum height, it starts falling freely. Let it strkes with the ground with velocity v'.

here, u = 0
So, 
It means the velocity is same as the velocity of projection.
Frequency=1/T, where T is the time period.
Reciprocal of frequency = T or it can be written as T = 1/f, where f is frequency.
The theoretic volume and pressure of a gas at zero Kelvin are zero. Moreover, there is zero kinetic energy present in the gas. This is because at zero Kelvin, none of the particles are moving.