Answer:
3.63m/s²
Explanation:
Given parameters:
Mass of box = 8kg
Net force = 29N
Unknown:
Acceleration of the box = ?
Solution:
To solve this problem, we use Newton's second law of motion which is stated as;
Force = mass x acceleration
Acceleration = 
= 
Acceleration = 3.63m/s²
Concentration :
196 g/L and 4 N
<h3> </h3><h3>Further explanation</h3>
The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight / volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.
500 cc of 2M H₂SO₄
V = 500 cc = 0.5 L
mol H₂SO₄
mass H₂SO₄ (MW = 98 g/mol)
concentration in g/L :
concentration in normality
Relationship between normality and molarity
N = M x n (n=valence , amount of H⁺ or OH⁻)
so :
Phase of matter
Explanation:
The phase of matter strictly is a function of its temperature. Matter exists in different phases at different temperatures.
- Matter is anything that has weight and occupies space.
- There are three states of matter:
- Solid
- Liquid
- Gas
These phases of matter depends on temperature.
For example;
- Water exists as gases above boiling point
- Water is also solid at freezing point.
- Between the freezing and boiling point, water is a liquid.
Learn more:
Chemistry brainly.com/question/8839455
#learnwithBrainly
Answer:
The number and the kinds of atoms in the compound
Explanation:
- A chemical formula of a compound contains symbols o the atoms of the elements present in the compound as well as the number of atoms of each element in the form of subscripts.
- Therefore it helps us to know the elements in a compound and the number of atoms in the compounds.
Answer:fH = - 3,255.7 kJ/mol
Explanation:Because the bomb calorimeter is adiabatic (q =0), there'is no heat inside or outside it, so the heat flow from the combustion plus the heat flow of the system (bomb, water, and the contents) must be 0.
Qsystem + Qcombustion = 0
Qsystem = heat capacity*ΔT
10000*(25.000 - 20.826) + Qc = 0
Qcombustion = - 41,740 J = - 41.74 kJ
So, the enthaply of formation of benzene (fH) at 298.15 K (25.000 ºC) is the heat of the combustion, divided by the number of moles of it. The molar mass od benzene is: 6x12 g/mol of C + 6x1 g/mol of H = 78 g/mol, and:
n = mass/molar mass = 1/ 78
n = 0.01282 mol
fH = -41.74/0.01282
fH = - 3,255.7 kJ/mol
