<span>First we can find the circumference of the whole circle with a radius of 5 feet.
circumference = 2 pi radius
circumference = (2 pi) (5 feet)
circumference = (10 pi) feet
From one high point to the other high point, the string moves through an angle of 10 degrees. Since a full circle is 360 degrees, this angle is 1/36 of a full circle.
Therefore, the arc length is 1/36 of the whole circumference.
arc length = (1/36) (circumference)
arc length = (1/36) (10 pi) feet
arc length = 0.873 feet</span>
Pluto would be placed 39.74 feet far from the Sun.
Astronomers use the gap between Earth and the sun, which is ninety-three million miles, as a new unit of measure called the Astronomical Unit.
Map scale refers to the connection (or ratio) between the space on a map and the corresponding distance on the ground. For example, on a 1:one hundred thousand scale map, 1cm at the map equals 1km on the ground.
The distance between the earth and solar, a = around 150 million km, is defined as one Astronomical Unit (AU). The radius of the solar, the solar is around 700,000 km.
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Answer:
I_v = 2,700 W / m^2
I_m = 610 W / m^2
I_s = 16 W / m^2
Explanation:
Given:
- The Power of EM waves emitted by Sun P_s = 4.0*10^26 W
- Radius of Venus r_v = 1.08 * 10^11 m
- Radius of Mars r_m = 2.28 * 10^11 m
- Radius of Saturn r_s = 1.43 * 10^12 m
Find:
Determine the intensity of electromagnetic waves from the sun just outside the atmospheres of (a) Venus, (b) Mars, and (c) Saturn.
Solution:
- We know that Power is related to intensity and surface area of an object follows:
I = P / 4*pi*r^2
Where, A is the surface area of a sphere models the atmosphere around the planets.
a)
- The intensity at the surface of Venus is calculated as:
I_v = P_s / 4*pi*r^2_v
I_v = 4.0*10^26 / 4*pi*(1.08*10^11)^2
I_v = 2,700 W / m^2
b)
- The intensity at the surface of Mars is calculated as:
I_m = P_s / 4*pi*r^2_m
I_m = 4.0*10^26 / 4*pi*(2.28*10^11)^2
I_m = 610 W / m^2
c)
- The intensity at the surface of Saturn is calculated as:
I_s = P_s / 4*pi*r^2_s
I_s = 4.0*10^26 / 4*pi*(1.43*10^12)^2
I_s = 16 W / m^2
<span>Negative is attracted to positive. </span>
D
The parent material refers the the rock that was responsible for the formation of a certain soil.
