Answer:
0.0619 m^3
Explanation
number of moles = n = 4.39 mol
pressure = P = 2.25 atm =2.25×1.01×10^5 Pa= 2.27×10^5 Pa
Molar gas constant =R = 8.31 J/(mol K)
Temperature T= 385K
volume of gas = V =?
BY GENERAL GAS LAW WE HAVE
PV = nRT
or V = nRT/P
or V = (4.39×8.31×385)/(2.27×10^5)
V = 0.0618728
V = 0.0619 m^3
On isolated ground receptacles, the metal yoke is not allowed to be integrally bonded to the equipment grounding terminal of the receptacle.
Any device with two distinct switches or receptacles is a duplex device. It can be shaped to fit a Decora opening or a typical duplex plate opening. It should be noted that they can be combination devices with a switch/outlet, switch/pilot light, etc.
Because of grounding connection removal and receptacle, it is utterly undesirable to connect the two bare equipment grounding conductors together directly.
The equipment grounding conductor associated with those circuits must be connected to the box when circuit conductors are terminated on equipment inside a metal box to prevent unneeded current discharge.
Learn more about grounding conductors here brainly.com/question/14886979
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Planet Y has rotated by 135.5° through during this time.
To find the answer, we need to know about the relation between angle and radius of orbit.
<h3>What's the expression of angle in terms of radius?</h3>
- Angle= arc/radius
- As arc = orbital velocity × time,
angle= (orbital velocity × time)/radius
- Orbital velocity= √(GM/radius), G= gravitational constant and M = mass of sun
- So, angle = (√(GM)× time)/radius^3/2
<h3>What's is the angle rotated by planet Y after 5 years, if ratio of the radius of orbit of planet X and Y is 4:3 and planet X is rotated by 88°?</h3>
- Let Ф₁= angle rotated by planet Y, Ф₂= angle rotated by planet X
- As time = 5 years ( a constant)
- Ф₁/Ф₂= (radius of planet X / radius of planet Y)^(3/2)
- Ф₁= (radius of planet X / radius of planet Y)^(3/2) × Ф₂
= (4/3)^(3/2) × 88°
= 135.5°
Thus, we can conclude that Planet Y has rotated by 135.5° through during this time.
Learn more about the orbital velocity here:
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Answer:
Explanation:
Let's use projectile motion equations. First of all we need to find the travel time. So we are going to use the next equation:
(1)
Where:
In this case:
Because the dog jumps horizontally
Let's asume the gravity constant as:
Because when the dog reach the base the height is 0
Now let's replace the data in (1)
Isolating t:
Finally let's find the horizontal displacement using this equation:
Replacing the data:
By definition;
Vd = I/nQA
In which,
Vd = drift speed = 0.000282 m/s
I = current through the wire = V/R = 16/0.1 = 160 Amps
n = Density of free electrons
Q = Fundamental charge = 1.6*10^-19 C
A = Cross-sectional area of the wire = πr^2 =π*0.003^2 = 2.827*10^-5 m^2
Rearranging the expression for Vd above and substituting;
n = I/VdQA = 160/(0.000282*1.6*10^-19*2.827*10^-5) = 1.254*10^29 free electrons/m^3
