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Snowcat [4.5K]
3 years ago
15

what is the resistance of a car light bulb that conducts 0.025A current when connected to a 12V car accumulator? is the current

in the bulb steady?
Physics
1 answer:
Sophie [7]3 years ago
7 0

One form of Ohm's Law says . . . . . Resistance = Voltage / Current .

R = V / I

R = (12 v) / (0.025 A)

R = (12 / 0.025) (V/I)

<em>R = 480 Ohms</em>

I don't know if the current in the bulb is steady, because I don't know what a car's "accumulator" is.  (Floogle isn't sure either.)

If you're referring to the car's battery, then the current is quite steady, because the battery is a purely DC storage container.

If you're referring to the car's "alternator" ... the thing that generates electrical energy in a car to keep the battery charged ... then the current is pulsating DC, because that's the form of the alternator's output.  

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If an object travels 15 metres in 5 seconds, what is the slope of its distance-time graph?
SOVA2 [1]

Answer:

3 m/s

Explanation:

The slope is distance divided by time, also known as 'speed'.

15 meters / 5 seconds = 3 meters per second.

8 0
3 years ago
(a) Write the energy equation for an elastic collision. (b) For an inelastic collision.
velikii [3]

Answer:

Explanation:

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(a) Elastic collision: When there is no loss of energy during the collision, then the collision is said to be elastic collision.

In case of elastic collision, the momentum is conserved, the kinetic energy is conserved and all the forces are conservative in nature.

The momentum of the system before collision = the momentum of system after collision

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(b) Inelastic collision: When there is some loss of energy during the collision, then the collision is said to be inelastic collision.

In case of inelastic collision, the momentum is conserved, the kinetic energy is not conserved, the total mechanical energy is conserved and all the forces or some of the forces are non conservative in nature.

The momentum of the system before collision = the momentum of system after collision

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4 years ago
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Read 2 more answers
A car is driving 25.5 m/s when it hits
IceJOKER [234]

Answer:

it takes the car 4.362 seconds to cover the distance of 88.4 m.

Explanation:

The distance the car covers is given by the function

x(t) = vt-\dfrac{1}{2}at^2,

where v = 25.5m/s , and a = 2.40m/s, putting  these in we get:

x(t) = 25.5t-\dfrac{1}{2}(2.4)t^2\\\\x(t) = 25.5t-1.2t^2

Now, when the car has moved to 88.4m, x(t) = 88.4 , or

x(t) = 25.5t-1.2t^2 = 88.4

which is a quadratic equation with solutions

t = 4.362s,\\t = 16.887s

We take the first solution t = 4.362s, <em>since at that time the car is still moving right and decelerating</em>. The second solution t =16.887 describes the situation where the car has stopped decelerating and is now moving leftwards because the decelerating is leftwards, <em>which is utterly wrong because we know that cars do not start moving backwards after the brakes have stopped them! </em>

Thus, it takes the car 4.362 seconds to cover the distance of 88.4 m.

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