i dont think their are a exact number
Answer:
226.8 mg of mupirocin powder are required
Explanation:
Given that;
weight of standard pack = 22 g
mupirocin by weight = 2%
so weight of mupirocin = 2% × 22 = 2/100 × 22 = 0.44 g
so by adding the needed quantity of mupirocin powder to prepare a 3% w/w mupirocin ointment
mg of mupirocin powder are required = ?, lets rep this with x
Total weight of ointment = 22 + x g
Amount of mupirocin = 0.44 + x g
percentage of mupirocin in ointment is 3?
so
3/100 = 0.44 + x g / 22 + x g
3( 22 + x g ) = 100( 0.44 + x g )
66 + 3x g = 44 + 100x g
66 - 44 = 100x g - 3x g
97 x g = 22
x g = 22 / 97
x g = 0.2268 g
we know that; 1 gram = 1000 Milligram
so 0.2268 g = x mg
x mg = 0.2268 × 1000
x mg = 226.8 mg
Therefore, 226.8 mg of mupirocin powder are required
The answer is dilute. A dilute salt solution contains a small amount of salt with high water concentration while a concentrated salt solution has a large amount of salt with a lower water concentration. Salt is inorganic hence it is not monounsaturated, which is a term related to organic compounds. The salt is unable to dissolve anymore in a saturated salt solution, leaving the undissolved salt at the bottom and this is not the case here since we only have a small amount of salt.
Answer:
Percentage error = 
x 100%
Explanation:
In order to calculate the percentage error in the student's calculation, the following formula will be used:
Percentage error = 
x 100%
experimental molar mass = 64 g/mol
theoretical molar mass = 58 g/mol
Hence, the expression becomes:
Percentage error = x 100%
Answer:
B) One way of solving this is to use dimensional analysis and cancel out grams to find volume.
A) density over mass is volume. Mass is 84.7 g and volume is 49.6 cm cubed
Explanation:
