Solution :
a). B at the center :
Here, one of the current is in the clockwise direction and therefore, the other current must be in the clockwise direction in order to cancel out the effect of the magnetic field that is produced by the other.
Therefore, the answer is ANTICLOCKWISE or COUNTERCLOCKWISE
b). Also, the sum of the fields must be zero.
Therefore,
So,
A
Therefore, the current in the outer wire is 24.38 ampere.
With the use of the formula SinФ = nλ / d, there are 16 spectral orders which can be seen when it is illuminated by white light.
Given that a grating has 2000 slits/cm. That is,
d = 0.01 / 2000
d = 5 x m
The wavelength λ = (700 - 400) nm
λ = 300 x m
To calculate how many full spectral orders that can be seen (400 to 700 nm) when it is illuminated by white light, we will use the below formula
SinФ = nλ / d
Φ = (nλ / d)
When n = 1
Φ = (300 x
/ 5 x
)
Φ = 3.4 degrees
when n = 2
Φ = (2 x 300 x
/ 5 x
)
Ф = 6.9 degrees
When n = 3
Ф = (3 x 300 x
/ 5 x
)
When n = 16
Ф = (16 x 300 x
/ 5 x
)
Ф = (0.96)
Ф = 73.7 degrees
when n = 17
Ф = (17 x 300 x
/ 5 x
)
Ф = (1.05)
Ф = Error ( that is, it does not exist)
Therefore, there are 16 spectral orders which can be seen when it is illuminated by white light.
Learn more about double slit here: brainly.com/question/4449144
Answer:
a. 3.039cm
b.magnetic field is
Explanation:
Direction of the solenoid magnetic field is along the axis of the solenoid. and magnetic field due to the wire perpendicular to that due to the solenoid.. Magnetic field at r is given by:
Angle of net magnetic field from axial direction is given by:
,
Field due to solenoid:
Field due to wire:
Therefore, r:
Hence, the radial distance is 3.039cm
b.The magnetic field strength is given by:
Hence, the magnetic field is
Answer:
Explanation:
As the final Kinetic energy is zero or less than initial kinetic energy, the collision must be inelastic.
In Inelastic collision both the bodies must stick together as final velocity is zero for both the bodies.
To conserve the momentum, momentum associated before the collision of first must be equal and opposite to the momentum associated with the second ball.
i.e.