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3 years ago

When you are using a crowbar to lift a large rock, you are working agents the force called

1 answer:

7 0

When you're using a crowbar to lift a large rock, you are working against the force called

$\boxed {\bf Gravity}$

$\bf Explanation:$
Gravity on Earth is what gives weight to all objects, it's defined as all things that have mass or energy are gravitated towards each other. Therefore when you're using a crowbar to lift a large rock, the weight is caused by gravity.

I hope this helps you!

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Assume that the radius ????r of a sphere is expanding at a rate of 70 cm/min.70 cm/min. The volume of a sphere is ????=43???????

rodikova [14]

Answer:

the rate of change in volume with time is 280πr² cm³/min

Explanation:

Data provided in the question:

Radius of the sphere as 'r'

$\frac{d\textup{r}}{\textup{dt}}$ = 70 cm/min

Volume of the sphere, V = $\frac{\textup{4}}{\textup{3}}\pi r^3$

Surface area of the sphere as 4πr²

Now,

Rate of change in volume with time, $\frac{d\textup{V}}{\textup{dt}}$

= $\frac{d(\frac{\textup{4}}{\textup{3}}\pi r^3)}{dt}$

= $3\times\frac{\textup{4}}{\textup{3}}\pi r^2}\times\frac{dr}{dt}$

Substituting the value of $\frac{dr}{dt}$

= $3\times\frac{\textup{4}}{\textup{3}}\pi r^2}\times70$

= 280πr² cm³/min

Hence, the rate of change in volume with time is 280πr² cm³/min

4 0

3 years ago

A 2-kg wheel rolls down the road with a linear speed of 15m/s. Find its trwansitional and rotational kinetic energies.

Elza [17]

Answer:

The translational kinetic energy is 225 J

The rotational kinetic energy is 225 J

Explanation:

Given;

mass of the wheel, m = 2-kg

linear speed of the wheel, v = 15 m/s

Transnational kinetic energy is calculated as;

E = ¹/₂MV²

where;

M is mass of the moving object

V is the velocity of the object

E = ¹/₂ x 2 x (15)²

E = 225 J

Rotational kinetic energy is calculated as;

E = ¹/₂Iω²

where;

I is moment of inertia

ω is angular velocity

$E = \frac{1}{2} I \omega^2\\\\E = \frac{1}{2} *mr^2*(\frac{v}{r})^2\\\\E = \frac{1}{2} *mr^2*\frac{v^2}{r^2} \\\\E = \frac{1}{2}mv^2$

E = ¹/₂ x 2 x (15)²

E = 225 J

Thus, the translational kinetic energy is equal to rotational kinetic energy

6 0

3 years ago

What is a true statement about the rotation period of the moon?

mrs_skeptik [129]

The time it takes for the Moon to rotate once around its axis is equal to the time it takes for the Moon to orbit once around Earth

5 0

3 years ago

explain in detail how you would test a gingerbread biscuit solution for the presence of starch, sugar, and protein

mixas84 [53]

To test a food for starch, you can add a few droplets of iodine to it, if the liquid changes to a blue/black color then starch is present. To test for sugar you can use Benedict's solution, which will also have a color change from blue to yellow/red/orange. Add Biuret Reagent solution to test for protein, the solution will turn a pink or purple color... Note that this may not improve the taste or color of your gingerbread biscuit though :)

5 0

3 years ago

*** PLEASE HELP EVEN FOR JUST ONE OF THE QUESTION WOULD REALLY HELP ME***

kondaur [170]

The distance covered in one orbit is equal to the circumference of earth.

Given that radius of earth is 3959 miles.

Circumference of earth= 2πr = 2*3.14*3959 = 24875.13 miles

Speed is 26,000 miles per hour.

Since, Velocity= Distance/Time

Time= Distance/Velocity = 24875.13/26000

Time = 0.9567 hours

Therefore,

Average hour per orbit is 0.957 approximately.

3 0

3 years ago