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3 years ago

When you are using a crowbar to lift a large rock, you are working agents the force called

1 answer:

7 0

When you're using a crowbar to lift a large rock, you are working against the force called

$\boxed {\bf Gravity}$

$\bf Explanation:$
Gravity on Earth is what gives weight to all objects, it's defined as all things that have mass or energy are gravitated towards each other. Therefore when you're using a crowbar to lift a large rock, the weight is caused by gravity.

I hope this helps you!

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The efficiency of a device such as a lamp can be calculated using this equation:

loris [4]

efficiency = (useful energy transferred ÷ energy supplied) × 100

It's easy to use this formula, but we have to know both the useful energy and the energy supplied. The drawing doesn't tell us the useful energy, so we have to find a clever way to figure it out. I see two ways to do it:

Way #1:

We all know about the law of conservation of energy. So we know that the total energy coming out must be 250J, because that's how much energy is going in. The wasted energy is 75J, so the rest of the 250J must be the useful energy . . . (250J - 75J) = 175J useful energy.

(useful energy) / (energy supplied) = (175J) / (250J) = 70% efficiency

================================

Way #2:

How much of the energy is wasted ? . . . 75J wasted

What percentage of the Input is that 75J ? . . . 75/250 = 30% wasted

30% of the input energy is wasted. That leaves the other 70% to be useful energy.

6 0

3 years ago

Read 2 more answers

A person walks 9.0 km directly east and then turns left and heads directly north for 12.0 km. What is his displacement from the

Readme [11.4K]

Explanation:

Given that,

A person walks 9.0 km directly east and then turns left and heads directly north for 12.0 km.

We need to find his displacement from the starting position.

We know that,

Displacement = shortest path covered

$D=\sqrt{9^2+12^2} \\\\D=15\ km$

For direction,

$\theta=\tan^{-1}(\dfrac{d_y}{d_x})\\\\\theta=\tan^{-1}(\dfrac{12}{9})\\\\= $$53.13^{\circ}$

Hence, this is the required solution.

5 0

3 years ago

The difference in a brass rod and steel rod is same as 12cm at all temperature .Find the length of the rod at 0°C.

egoroff_w [7]

Answer:

I think its 12 cm itself. Because in the question it is said that the length is same in all temperature

5 0

3 years ago

On which variable does magnetic flux depend?A) the magnetic fieldB)the orientation of the field with respect to the region throu

hram777 [196]

Answer:

D) All of these

Explanation:

The magnetic flux through a coil of wire is given by:

$\Phi = BA cos \theta$

where

B is the intensity of the magnetic field

A is the area enclosed by the coil

$\theta$ is the angle between the direction of B and the normal to the area of the coil

Therefore, we see that the magnetic flux depends on all these quantities:

A) the magnetic field

B)the orientation of the field with respect to the region through which it passes

C)the area of a region through which magnetic field passes

So, the correct answer is

D) All of these

4 0

3 years ago

Railroad car A, with mass 6275 kg, is traveling east at 6.5 m/s along a straight track. It strikes railroad car B, with mass 515

LekaFEV [45]

The speed of A and B immediately after collision is 5.28m/s

Explanation:

Mass of A is 6275kg

Speed of A is 6.5m/s

Mass of B is 5155kg

Speed of B is 3.8m/s

Track is frictionless.

A and B stick together.

speed of attached A and B = ?

mₐsₐ + mᵇsᵇ = (mₐ + mb) s

$6275 X 6.5 + 5155 X 3.8 = ( 6275 + 5155) X s\\\\s = \frac{40787.5 + 19589}{11430}\\ \\s = \frac{60376.5}{11430}\\ \\s = 5.28m/s$

Therefore, The speed of A and B immediately after collision is 5.28m/s

4 0

3 years ago