Answer:
139 N
Explanation:
Thats the answer on e2020
The dog is 85kg or 187lbs (pounds)
A & C
Explanation:
The combination of the earth's weak gravity and its closeness to the sun does not allow it to hold hydrogen and helium gases in its atmosphere. Its relative closeness to the sun means it is hot enough such that the helium and hydrogen molecules would have high kinetic energy. Remember that gravity acts strongly on larger masses, therefore it would require very strong gravity to have an influence on lighter gas molecules like hydrogen and helium let alone when they have a high kinetic energy. This means these molecules can easily escape the earth’s atmosphere into space.
Planets that are larger (meaning they have a stronger gravity) and farther from the sun (meaning these molecules won't have a very high kinetic energy) are able to hold these lighter gases in their atmosphere. Examples of such planets are Jupiter.
Learn More:
For more on gravity check out;
brainly.com/question/8844454
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Answer:
It has no effect on the amplitude.
Explanation:
When the sandbag is dropped, then the cart is at its maximum speed. Dropping the sand bag does not affect the speed instantly, this is because the energy remains within the system after the bag as been dropped. The cart will always return to its equilibrium point with the same amount of kinetic energy, as a result the same maximum speed is maintained.
Answer:
The collision is not elastic. The system increases his kinetic energy m*v₀² times.
Explanation:
Assuming no external forces acting during the collision, total momentum must be conserved.
Considering the information provided, we can write the momentum conservation equation as follows:
m*v₀ = -m*v₀ + 2*m*vf
Solving for vf, we arrive to this somehow surprising result:
vf = v₀ (in the same direction that m was moving before the collision).
In order to determine if the collision was elastic, or not, we need to calculate the kinetic energy of the system before and after the collision:
K₀ = 1/2*m*v₀²
Kf = 1/2*m*v₀² (due to the object of mass m, as the kinetic energy is always positive) + 1/2 (2m) * v₀²
⇒Kf = 1/2*m*v₀² + 1/2 (2m) * v₀² = 3/2*m*v₀²
ΔK = Kf - K₀ = 3/2*m*v₀² - 1/2*m*v₀² = m*v₀²
As there is a net difference between the final and initial kinetic energies, and the total kinetic energy must be conserved in an elastic collision (by definition) we conclude that the collision is not elastic, and the change in the kinetic energy of the system is equal to m*v₀².
